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2 years ago

If the function 5x + y = 1 has the domain {-2, 1, 6}, then what is the corresponding range?

Mathematics

2 answers:

inysia [295]2 years ago

6 0

Answer:

{ 11, -4, -29}

Step-by-step explanation:

5(-2) + y = 1

-10 + y = 1

y = 11

5(1) + y = 1

y = -4

5(6) + y = 1

30 + y = 1

y = -29

hammer [34]2 years ago

3 0

Answer:

The Range is the set: { -29, -4, 11 }

Step-by-step explanation:

You need to apply the given function to the x-values of the Domain, to find what values of the Range they are associated with. So let's start by isolating y on one side of the expression:

y = 1 - 5 x

Now let's find what values they result when x = -2, 1, and 6:

y = 1 - 5 (-2) = 1 + 10 = 11

y = 1 - 5 (1) = 1 - 5 = -4

y = 1 - 5 (6) = 1 - 30 = -29

Therefore the Range is the set: { -29, -4, 11 }

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A toy train has 8 compartments and an engine that is 8 inches long. Each compartment is 4 inches long. Each compartment is joine

luda_lava [24]

Answer:

64in

Step-by-step explanation:

links=8*3=24

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2 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

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3 years ago

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Artyom0805 [142]

Answer:

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Step-by-step explanation:

For this problem, we have to solve for the inequality.

9a - 24 > 48

add 24 on both sides of the inequality.

9a > 72

Divide 9 on both sides of the inequality.

a > 8

So, your solution would be a > 8.

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3 years ago

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erica [24]

Answer:

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