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mixas84 [53]
3 years ago
11

If the function 5x + y = 1 has the domain {-2, 1, 6}, then what is the corresponding range?

Mathematics
2 answers:
inysia [295]3 years ago
6 0

Answer:

{ 11, -4, -29}

Step-by-step explanation:

5(-2) + y = 1

-10 + y = 1

y = 11

5(1) + y = 1

y = -4

5(6) + y = 1

30 + y = 1

y = -29

hammer [34]3 years ago
3 0

Answer:

The Range is the set: { -29, -4, 11 }

Step-by-step explanation:

You need to apply the given function to the x-values of the Domain, to find what values of the Range they are associated with. So let's start by isolating y on one side of the expression:

y = 1 - 5 x

Now let's find what values they result when x = -2, 1, and 6:

y = 1 - 5 (-2) = 1 + 10 = 11

y = 1 - 5 (1) = 1 - 5 = -4

y = 1 - 5 (6) = 1 - 30 = -29

Therefore the Range is the set: { -29, -4, 11 }

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Find the period of the function. y=3 sin x/8
Alexus [3.1K]

Answer:

The period of given function is  Period = 16\pi

So, Option B is correct.

Step-by-step explanation:

In this question we need to find the period of the function y= 3 sin x/8

The formula used to find period of function is: \frac{2\pi }{b}

We need to know the value of b.

To find the value of b we compare the standard equation with the equation of function given.

Standard Equation: y = a sin(bx - c) +d

Given Equation: y= 3 sin(x/8)

Comparing we get:

a= 3

b= 1/8

c= 0

d=0

So, we get the value of b i.e 1/8. Putting it in the formula to find period of given function.

Period = \frac{2\pi }{b}

Period = \frac{2\pi }{\frac{1}{8}}

Solving,

Period = 2\pi *8

Period = 16\pi

So, the period of given function is  Period = 16\pi

5 0
3 years ago
Find the length of the side of a square with area 225 square units
givi [52]

you can find the length of the side of a square by square rooting the area, which is 225. the square root of 225 is 15
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MA_775_DIABLO [31]

Answer:

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Step-by-step explanation:

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c=18.84

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