The error made by Tnaya in constructing the box plot is the first quartile and third quartile depicited is wrong.
<h3>What is a box plot?</h3>
A box plot is used to study the distribution and level of a set of data. The box plot consists of two lines known as whiskers and a box. The first whisker represents the minimum value and the last whisker represents the maximum value.
On the box, the first line to the left represents the first quartile. 25% of the score represents the lower quartile. The next line on the box represents the median. 50% of the score represents the median. The third line on the box represents the third quartile. 75% of the scores represents the third quartile.
For the data given, the:
- Minimum value = 12
- Maximum value = 22
- Median = 16
- First quartile = 11/4 = 2.75 = 13
- Third quartile = 3/4 x 11 = 8.25 = 23
To learn more about median, please check: brainly.com/question/20434777
Step-by-step explanation:
Percentage decrease = 30% × 25
New value = 25 - Percentage decreaseNew value =
25 - Percentage decrease =
25 - (30% × 25) =
25 - 30% × 25 =
(1 - 30%) × 25 =
(100% - 30%) × 25 =
70% × 25 =
70 ÷ 100 × 25 =
70 × 25 ÷ 100 =
1,750 ÷ 100 =
17.5
Absolute change (actual difference) =
New value - 25 =
17.5 - 25 =
- 7.5
Using the normal distribution, it is found that:
- 3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
- 3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.
- 4 - a) The 25th percentile for the math scores was of 71.6 inches.
- 4 - b) The 75th percentile for the math scores was of 78.4 inches.
<h3>Normal Probability Distribution
</h3>
In a <em>normal distribution </em>with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
Question 3:
- The mean is of 73 inches, hence
.
- The standard deviation is of 3 inches, hence
.
Item a:
The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.




The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
Item b:
The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.




The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.
Question 4:
- The mean score is of 75, hence
.
- The standard deviation is of 5, hence
.
Item a:
The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.




The 25th percentile for the math scores was of 71.6 inches.
Item b:
The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.




The 75th percentile for the math scores was of 78.4 inches.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213
Answer: It's an unfair method because two or more students could get the same results./ D
Step-by-step explanation: hope this helps