The average of three different positive integers is 8. What is the largest integer that could be one of them.
1 answer:
Supposing that the integers are x, y and z, and that their average is 8, then
x+y+z
-------- = 8, or x + y + z = 24.
3
Let's experiment. Making up a table, we get:
x y z sum (sum MUST be 24)
5 9 10 24
4 9 11 24
3 10 11 24
2 11 11 24
1 11 12 24
1 10 13 24
1 1 22 24
Can't choose integers smaller than 1, so it appears that 22 is the largest possible integer that could be one of x, y and z.
You might be interested in
Answer:
329.45833333333
Step-by-step explanation:
Answer:
HI!
Step-by-step explanation:
BYE!
Sorry :(
You must first simplify the radicals by taking out any perfect squares.
√8 + 3√2 + √32 =
√4 * √2 + 3√2 + √16 * √2 =
2√2 + 3√2 + 4√2 =
9√2
I have no clue but i wish you the best of luck