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marusya05 [52]
3 years ago
14

The average of three different positive integers is 8. What is the largest integer that could be one of them.

Mathematics
1 answer:
Trava [24]3 years ago
7 0
Supposing that the integers are x, y and z, and that their average is 8, then

x+y+z
-------- = 8, or x + y + z = 24.
    3

Let's experiment.    Making up a table, we get:

x   y   z   sum (sum MUST be 24)
5  9  10    24
4  9   11    24
3  10  11   24
2   11 11    24
1   11  12   24
1   10  13   24
1    1   22   24

Can't choose integers smaller than 1, so it appears that 22 is the largest possible integer that could be one of x, y and z.
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Explain why the expression 7•3x is not equal to the expression 21x
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I’ll give brainliest please help asap :D
USPshnik [31]
<h3>Answer:</h3><h3> C</h3><h3 /><h3>Step-by-step explanation:</h3><h3>It is C.</h3>

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4 0
2 years ago
A number plus itself, plus twice itself, plus 4 times itself is equal to -104
NARA [144]

The scenario will will be represented by: x+x+2x+4x=-104

The number will be -13

Step-by-step explanation:

We have to convert the given situation into the mathematical form

Let x be the number

Then

"a number plus itself"

x+x

"plus twice itself"

x+x+2x

"plus 4 times itself"

x+x+2x+4x

"is equal to -104"

x+x+2x+4x=-104

This can also be written as:

x+x+2x+4x=-104\\8x=-104\\Dividing\ both\ sides\ by\ 8\\\frac{8x}{8}=\frac{-104}{8}\\x=-13

Keywords: Linear Equation

Learn more about linear equation at:

  • brainly.com/question/2150928
  • brainly.com/question/2154850

#LearnwithBrainly

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