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3 years ago

14

The average of three different positive integers is 8. What is the largest integer that could be one of them.

1 answer:

Trava [24]3 years ago

7 0

Supposing that the integers are x, y and z, and that their average is 8, then

x+y+z
-------- = 8, or x + y + z = 24.
3

Let's experiment. Making up a table, we get:

x y z sum (sum MUST be 24)
5 9 10 24
4 9 11 24
3 10 11 24
2 11 11 24
1 11 12 24
1 10 13 24
1 1 22 24

Can't choose integers smaller than 1, so it appears that 22 is the largest possible integer that could be one of x, y and z.

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What is the range of y = –5sin(x)?

sergejj [24]

Answer:

$-5\leq y\leq5$ is the required range.

Step-by-step explanation:

We have been given a function:

$y=-5sin(x)$

The range of sin x is $-1\leq sinx\leq1$

multiply -5 in each term of the above equation.

$-1(-5)\geq -5sinx\geq-5$

$\Rightarrow 5\geq -5sinx\geq-5$

Hence, the required range is:

$-5\leq -5sinx\leq5$

replace -5sinx by y so, we get:

$-5\leq y\leq5$

4 0

3 years ago

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Help me i need help ok try to explain and ok ok ok ok ok ok ok ok

Kaylis [27]

Question 9

18, 28, 6, 54

Question 10

Correct Number: 5

Incorrect Number: 6

7 0

2 years ago

Please help me with question 5!!!!!!!!!

allsm [11]

Answer:

a)2,3,4,5,6

b)-3,-1,1,3,5

Step-by-step explanation:

a) y(-2)=-2+4=2

y(-1)=-1+4=3

y(0)=0+4=4

y(1)=1+4=5

y(2)=2+4=6

b)y=2x+1

y(-2)=2*(-2)+1=-3

y(-1)=2*(-1)+1=-1

y(0)=2*0+1=1

y(1)=2*1+1=3

y(2)=2*2+1=5

6 0

3 years ago

Read 2 more answers

What is the minimum value of C = 7x + 8y, given the constraints: 2x + y ≥ 8, x + y ≥ 6, x ≥ 0, y ≥ 0. A. 32 B. 42 C. 46 D. 64

marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are $2x+y\geq 8$ -------(1)

$x+y \geq 6$ ------------- (2)

$x \geq 0$ , $y \geq 0$ -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

And, $2\times 0+0\geq 8$ ⇒ $0\geq 8$ ( false)

Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, $0+0\geq 6$ ⇒ $0\geq 6$ ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4), C= 46

At B≡(6,0), C= 42

Thus at B, C is minimum, And its minimum value = 42

5 0

3 years ago

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Make x the subject of the formula y= b/ax

neonofarm [45]

Answer:

x=b/(ay)

Step-by-step explanation:

To make x the subject of the formula, we basically have to isolate the x.

To do this we first multiply both sides by x.

xy=b/a

Now, to isolate the x, we simply divide by y,

x=b/(ay)

So x=b/(ay) is our answer

8 0

3 years ago