Given:
The first two terms in an arithmetic progression are -2 and 5.
The last term in the progression is the only number in the progression that is greater than 200.
To find:
The sum of all the terms in the progression.
Solution:
We have,
First term : 
Common difference : 


nth term of an A.P. is

where, a is first term and d is common difference.

According to the equation,
.



Divide both sides by 7.

Add 1 on both sides.

So, least possible integer value is 30. It means, A.P. has 30 term.
Sum of n terms of an A.P. is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Substituting n=30, a=-2 and d=7, we get
![S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D%5Cdfrac%7B30%7D%7B2%7D%5B2%28-2%29%2B%2830-1%297%5D)
![S_{30}=15[-4+(29)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B%2829%297%5D)
![S_{30}=15[-4+203]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B203%5D)


Therefore, the sum of all the terms in the progression is 2985.
1.)11x^2-3x
2.)8x+1-x^2
3.)-x^2-x+8
4.)-2y+10-x^2
Answer:400
Step-by-step explanation: multiply the volume value of 2.4 liters by 1000 then divide by 6
2.4*1000/6
√20 the prime factors are 2, 2, 5 so
-2 * √4 *√5
-2*2*√5
-4√5 is the first part ,
now for √125, use prime factorization ,
all prime factors that make up 125 is
5, 5, 5 so √125 can be separated to √25√5 and √25 = 5 so the second part is 5√5.
now -4√5 - 5√5 = -9√5.
therefore answer is -9√5