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3 years ago

The graph shows how the distance an object traveled changed over time.

1 answer:

5 0

The right answer for the question that is being asked and shown above is that: "C. The object traveled the greatest distance between points C and D because that line has the greatest slope." The statement that accurately summarizes the data from this graph is that t<span>he object traveled the greatest distance between points C and D because that line has the greatest slope.</span>

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A 5 kg bowling ball travelling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1

Ilia_Sergeevich [38]

Answer:

1.5 m/s

Explanation:

Conservation of momentum means the momentum of the system before the collision is the same as after.

The before, after momentum of each ball is ...

5 kg ball: (5 kg)(2 m/s), (5 kg)(-1 m/s)

10 kg ball: (10 kg)(0 m/s), (10 kg)(v)

The sum of the "before" products is the same as the sum of the "after" products:

(5 kg)(2 m/s) +0 = (5 kg)(-1 m/s) +(10 kg)v

(10 +5) kg·m/s = (10 kg)·v . . . . . add (5 kg)(1 m/s) to both sides

v = (15 kg·m/s)/(10 kg) = 1.5 m/s

The speed of the larger ball will be 1.5 m/s. Its direction of motion will be the opposite of that of the 5 kg ball after the collision.

7 0

3 years ago

A) A wire made from iron with a cross-section of diameter 0.800 mm carries a current of 14.0 A. Calculate the "areal current den

Veseljchak [2.6K]

Answer:

A) ρ= $1.74x10^{26}$

B) μ= $1.68x10^{29}\frac{electron}{m^3}$

C) v= $1.03x10^{-3}\frac{m}{s}$

D)e= $8.99x10^-9$

Explanation:

The magnetic field can be find knowing the current is the charge per second

β= $\frac{14eC*s}{1.6x10^{-19}C}\\$

β= 8.75x10^{19}e*s

Electron density

ρ= $\frac{8.75x10^{19}}{\pi*0.400x10^{-3}m} = 1.74x10^{26}$

μ= $\frac{7.86}{56.2}\frac{g}{cm^3} \frac{mol}{g}*6.022x10^{23}\frac{molecules}{mol} *2 \frac{electron}{molecule}$

μ $=1.68x10^{23} \frac{electron}{cm^3}= 1.68x10^{29} \frac{electron}{m^3}$

The drift speed using last information found

$v= \frac{J}{n*q} \\v= \frac{14A}{\pi*((0.40x10^-3)^2)*1.68x10^29*1.60x10^-19)} = 1.03x10^-3(\frac{m}{s} )$

To compared the random thermal motion and the current's drift speed

$e=\frac{1.03x10^-3}{1.15x10^5} = 8.99x10^-9$

8 0

3 years ago

What does electrons and the nucleus have in common?

timama [110]

<span>All atoms of the same element have the same number of protons in the nucleus and consequently have the same atomic number. All atoms of the same neutral element have the same number of electrons as well.</span>

8 0

4 years ago

Attached here is the question:

ICE Princess25 [194]

Answer:

t = 6 [s]

Explanation:

In order to solve this problem we must first use this equation of kinematics.

$v_{f}^{2}=v_{o}^{2} +2*a*x$

where:

Vf = final velocity = 0 (the car comes to rest)

Vo = initial velocity = 72 [km/h]

a = acceleration [m/s²]

x = distance = 60 [m]

First we must convert the velocity from kilometers per hour to meters per second.

$72 [\frac{km}{h}]*\frac{1000m}{1km} *\frac{1h}{3600s} =20 [m/s]$

$0=(20)^{2} -2*a*60\\400 = 120*a\\a=3.33[m/s^{2} ]$

Now using this other equation of kinematics.

$v_{f}=v_{o}-a*t$

0 = 20-3.33*t

t = 6[s]

5 0

4 years ago

Your odometer of your car says 54 123 miles when you start your trip, your watch says 9 45 AM When you get to your

strojnjashka [21]

Answer:

27 mph

Explanation:

9:45 to 11:45 = 2 hours

odometer says you traveled 54 miles in 2 hours or 27 mph

5 0

3 years ago