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avanturin [10]
2 years ago
6

What must change in order for electromagnetic induction to occur in a wire coil?.

Physics
1 answer:
mihalych1998 [28]2 years ago
4 0

Answer:

The magnetic field through the coil must change.

Explanation:

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If the frog lands with a velocity equal to its average velocity and comes to a full stop 0.25s later, what is the frog’s average
Nina [5.8K]

Answer:

Average accelation = -4V

Explanation:

a=\frac{V-V0}{t}

V=0 m/s (because the frog stopped)

V0 = V (average velocity)

t= 0,25 s

So;

a=\frac{V-V0}{t}=\frac{0-V}{0.25}=-4V

4 0
3 years ago
What are the body parts to this figure? Any of the body parts. (Please)
vlabodo [156]
1 - Skull
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3 - Scapula
4 - Sternum
5 - Ulna
6 - Radius
7 - Pelvis
8 - Femur
9 - Patella
10 - Tibia
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14 - Ribs (rib cage)
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3 0
3 years ago
Which of the following properties of water help to explain why icebergs float in the ocean?
crimeas [40]
The reason why icebergs float in the ocean has to do with temperature. Icebergs are colder than the ocean water and therefore the cold water is less dense than the warm water and this causes the Iceberg to float.
7 0
3 years ago
A kite 40 ft above the ground moves horizontally at a constant speed of 10 ft/s, with a child, holding the ball of kite string,
Lorico [155]

Answer:

 v = 27.28 m /s, θ = 63.9º

Explanation:

For this exercise we can approximate the movement to a projectile launch, let's analyze the situation.

* We must find the horizontal speed, for this we will find the descent time and the horizontal distance

* We look for the vertical speed

At the highest point the speed is horizontal

Let's find the time it takes for the kite to reach the ground

             y = y₀ + v_{oy} t - ½ g t²

             0 =y₀ + 0 -1/2 gt²

             t = \sqrt{ \frac{2y_o}{g} }

             t = √(2 40/32)

             t = 2.5 s

to find the horizontal velocity we must know the horizontal distance, let's use trigonometry

          sin θ = y / l

          θ = sin⁻¹1 y / l

          θ = sin⁻¹ 40/50

          θ = 53.1º

therefore the horizontal distance is

          x = l cos 53.1

          x = 50cos 53.1

          x = 30 m

let's use the equation

          x = v₀ₓ t

          v₀ₓ = x / t

          v₀ₓ = 30 / 2.5

          v₀ₓ = 12 m / s

we look for the vertical component of the velocity

          v_y = v_{oy} - g t

          v_y = 0 - g t

          v_y = - 9.8 2.5

          v_y = -24.5 m / s

the negative sign indicates that the speed is directed downwards, because it is the arrival point, as they indicate that there is no friction, the exit speed is the same, worse with the opposite sign

We already have the two components of the velocity, let's use the Pythagorean theorem to find the modulus

          v = \sqrt{v_x^2 + v_y^2}

          v = \sqrt{12^2 + 24.5^2}

          v = 27.28 m /s

we use trigonometry for the angle

          tan θ = v_y / vₓ

          θ = tan⁻¹ v_y / vₓ

          θ = tan⁻¹ 24.5 / 12

          θ = 63.9º

4 0
3 years ago
If a 66.0-kg person stands with both feet on the same step, what is the gravitational potential energy of this person on the fir
Leokris [45]

Answer:

U₁ = 129.4 J

Explanation:

The potential energy is

    U = mg y - m g y₀

Where I correspond to the initial position, with this it is an additive constant, we can make it zero with the placement of the reference system, in this case the system is placed on the floor where the ladder rests.

The power power for people on the floor is

     U₀ = 0 J

The potential energy for the person on the first step is

   U₁ = m g y₁

In general the steps are 20 cm high

     y₁ = 20 cm (1m / 100cm) = 0.20 m

     U₁ = 66 9.8 0.20

     U₁ = 129.4 J

8 0
3 years ago
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