10 x 4^2 = 160 / 8..
V = 20m/s...
...x 8 = 100 miles,meters, metric what ever m stands for after 8 seconds.
This is my guess since the problem says 4m/s^2
V= distance/ ST (traveled/used)
Answer:
Angular velocity = 0.105 rads⁻¹
speed of tip = 0.00105 ms⁻¹
Explanation:
A second hand turns 2π rad each 60 sec
Thus: it has an angular speed given by
ω = 2π/T = 2π/60 = π/30 = 0.105 rad s⁻¹
The speed of the tip is given by
V= rω = 0.01 m × (0.105 rads⁻¹)
= 0.00105 ms⁻¹
Answer:
The length of the moment arm is 19 cm
Explanation:
Given;
The total length of the ruler, L = 40 cm
a mass is hung from its center mass, at 21 cm
a force, F is applied at 40 cm
The length of the moment arm is calculated as;
the center mass of the ruler is at 20 cm mark
0 21cm 40cm
--------------------------------------------------------------------
↓ r ↓
M F
Moment about F, = Fr
The length of the moment arm is = r
r = 40 cm - 21 cm
r = 19 cm
Therefore, the length of the moment arm is 19 cm
Explanation:
Given that,
The kinetic energy of the electron,
Radius of the orbit, r = 37.4 cm = 0.374 m
To find,
(a) the electron's speed, (b) the magnetic field magnitude, (c) the circling frequency, and (d) the period of the motion.
Solve,
We know that,
(a) The formula of the kinetic energy is given by :
v is the speed if electron
m is the mass of electron
(b) Let B is the magnitude of magnetic field. On the circular path the magnetic field is given by :
(c) Let T is the time period of the motion. It is given by :
Circling frequency is given by :
(d) The period of motion,
Answer:
The answer is that the worker should not be worried.
Explanation:
At equilibrium position, the net torque is equal to zero
∑tnet = 0
((-mg) * (D/2)) + ((-mg) * (D-d)) + (T * sinθ * D) = 0
Clearing the tension in the cable T:
Since this tension (14727.24 N) is less than the nominal tension (15354 N), the worker should not be concerned.