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3 years ago

An exercise program that lacks specific goals is failing what fitness principle?

Physics

2 answers:

rusak2 [61]3 years ago

8 0

An exercise program that lacks specific goals is failing into the specificity principle of fitness.

Further Explanation:

The fitness program helps in achieving good health. To start the fitness program we have to make fitness goals, create a healthy diet. Physical fitness is the capability of a body to perform daily activity.

Specificity is occurring in a specific reaction that occurs as a result of the exercise program. Specificity increases the long-term adaptations to occur with progressive overload. Specificity—a focus on particular movements, muscles, velocity and energy systems —drives the gains you make in training and practice. If an individual doesn't intentionally train for something, it may not occur.

The specificity principle states that these physiologic or metabolic changes are specific to the cardiorespiratory, neurologic and muscular responses that are entailed by the exercise activity. SAID (Specific Adaptations to Imposed Demands) is a common term of specificity principle. Physical fitness helps us to prevent heart disease, lung cancer, stroke, and type II diabetes. Progress of a fitness program is very slow it takes time. It is more difficult to maintain a program for a long time with the same enthusiasm. We can set the goal and check whether we are progressing or not.

Learn more:

Learn more about carbohydrate monomer <u>brainly.com/question/6947177 </u>
Learn more about core muscle stabilization <u>brainly.com/question/1231927 </u>
Learn more about energy storage <u>brainly.com/question/523624 </u>

Answer Details:

Grade: High School

Subject: Health

Chapter: Fitness Program

Keywords:

Physical fitness, healthy diet, heart disease, cancer, fitness program, goal, specificity, evaluation, fitness program, adaptation, cancer, stroke, response.

lbvjy [14]3 years ago

6 0

The answer is progression

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2 years ago

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3 years ago

A proton, starting from rest, accelerates through a potential difference of 1.0 kV and then moves into a magnetic field of 0.040

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r = 0.11 m

Explanation:

The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force ( $F_{B}$ ), as follows:

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<u>Where:</u>

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<em>v: is the proton's velocity</em>

<em>r: is the radius of the proton's orbit</em>

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<em>B: is the magnetic field = 0.040 T </em>

Solving equation (1) for r, we have:

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$K = U \rightarrow \frac{1}{2}mv^{2} = q*\Delta V$ (3)

<u>Where:</u>

<em>K: is kinetic energy</em>

<em>U: is electrostatic potential energy</em>

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Solving equation (3) for v, we have:

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Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:

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Therefore, the radius of the proton's resulting orbit is 0.11 m.

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3 years ago