Answer:
measured at constant temperature and pressure
Hope this helps :)
Answer:
2.8351×10^7 N/kg
Explanation:
We know that,
W = mg -------(1)
where W = weight, m = mass, g = gravitational acceleration
Also from Newton's law of gravitation we know that,
F = GMm/r²
Where,
F = gravitational force,
G = universal gravitational constant
M,m = masses of object under gravitational influence
r = distance between the two center of masses.
Here we get
F = (Gm/r²)M -------(2)
From 1 and 2
The acceleration due to gravity = gravitational field intensity
So if you consider the gravitational field intensity at the surface of the asteroid,it is equal to the acceleration due to gravity at the same place.
So we get,
g = (6.67×10^-11)×9.3835×10^20/(47²) = 2.8351×10^7 N/kg
Answer:
0.541 nm
Explanation:
The condition for maxima is,
Here, m=0,1,2,.....
And d is the slit separation, m is the order of maxima, 
is the wavelength.
Given that, the 17.3 eV electron posses a wavelength of
And the order of maxima is 
.
And the angle at which first order maxima occur is, 
.
Put these values in maxima condition while solving for d.
Therefore, the slit separation is 0.541 nm.
Answer:
Explanation:
Angular velocity of satellite
= 2π x .01
= .02 π rad /s
Initial angular momentum
Moment of inertia x angular velocity
= 2000 x .02 π
= 125.6 unit
Linear impulse produced by each thruster
= 15 N.s
Angular impulse
= 15 x 1.5 = 22.5 unit
Total angular impulse in 30 pulses
= 22.5 x 2 x 30
1350
This angular impulse will add total angular momentum of
1350 unit
So total angular momentum after 30 pulses
= 1350 + 22.5
= 1372.5 unit
So final angular velocity
= final angular momentum / moment of inertia
= 1372.5 / 2000
= 0 .686 rad /s
