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Allushta [10]
3 years ago
12

An object is fired from the ground at 100. m/s at an angle of 30° with the horizontal.

Physics
1 answer:
Softa [21]3 years ago
7 0

Answer:

a. V_y = 50m/s and V_x = 86.6m/s

b. d_x = 173.2m

c. d_y = 80.38m

Explanation:

V_x = 100m/s*cos(30°)

V_x = 86.6m/s

V_y = 100m/s*sin(30°)

V_y = 50m/s

D_x = v_x*t

d_x = 86.6m/s*2s

d_x = 173.2m

v_f = 50m/s+(-9.81m/s²)*2s

v_f = 30.38m/s

d_y = .5*(30.38m/s+50m/s)*2s

d_y = 80.38m

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Answer:

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Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

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W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

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