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goldenfox [79]
3 years ago
15

Two students stand poised to leap off a high dive structure into the swimming pool below. Student B is twice as massive as stude

nt A. Which of the following is true?
A. Student B will reach the ground sooner than student A.
B. Both students have the same gravitational potential energy.
C. Both students will have the same kinetic energy just before impact.
D. Student B did twice as much work climbing to the top of the structure
Physics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer: option (D)

Explanation:

The potential energy of each of the students is given below as

P.E(student A) = mgh, where m = mass of student A, g is acceleration due to gravity and h = height of the high dive structure.

The mass of student B is twice as much as that of A, hence his mass is 2m and his potential energy is given below as

P.E ( student B) =2mgh = 2(mgh)

Recall that the relationship between potential energy and work done is that

Work done = - (change in potential)

For student A, work done = - mgh

For student B, work done = - 2mgh

From the equations above it can be seen that student B will do twice the work in getting to the high dive structure than student A hence validating option D.

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1 year ago
A 24.0 cm long screwdriver is used as a lever to open a can of paint. If the fulcrum is 0.500 cm away from the end of the screwd
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The ideal mechanical advantage of the screwdriver is 47

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d_o is the distance of the output force from the fulcrum

In this problem, we have:

d_o = 0.500 cm, since the fulcrum is 0.500 cm from the end

d_i = 24.0 cm - 0.500 cm = 23.5 cm (the distance between the fulcrum and the point where are we holding the screwdriver)

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7 0
3 years ago
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4 years ago
A 0.38 kg drinking glass is filled with a hot liquid. The liquid transfers 7032 J of energy to the glass. If the
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Answer:

841  J/kg.K

Explanation:

The computation of the specific hear of the glass is shown below:

As we know that

E= cmΔt

where

c denotes specific heat

m denotes 0.38 kg

Δt = temperature = 22k

E denotes energy = 7032 J

Now

7032 J = (0.38) (22) (c)

7032 J = 8.36 (c)

So C = 7032 J ÷ 8.36

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7 0
3 years ago
4.72 A full-wave bridge-rectifier circuit with a 1-k load operates from a 120-V (rms) 60-Hz household supply through a 12-to-1 s
melisa1 [442]

Answer:

a) 12.74 V

b) Two pairs of diode will work only half of the cycle

c) 8.11 V

d) 8.11 mA

Explanation:

The voltage after the transformer is relationated with the transformer relationshinp:

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the peak voltage before the bridge rectifier is given by:

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The diodes drop 0.7v, when we use a bridge rectifier only two diodes are working when the signal is positive and the other two when it's negative, so the peak voltage of the load is:

V_l=V_{op}-2(0.7)\\V_l=12.74V

As we said before only two diodes will work at a time, because the signal is half positive and half negative,so two of them will work only half of the cycle.

The averague voltage on a full wave rectifier is given by:

V_{avg}=2*\frac{V_l}{\pi}\\V_{avg}=8.11V

Using Ohm's law:

I_{avg}=\frac{V_{avg}}{R}\\\\I_{avg}=8.11mA

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