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Luba_88 [7]
3 years ago
9

Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive

object; the ring has a diameter of about 18 light-years and an orbital speed of about 180 km/s. answers
Physics
1 answer:
Setler [38]3 years ago
5 0

Answer:

The mass of the massive object at the center of the Milky Way galaxy is 3.44\times10^{37}\ Kg

Explanation:

Given that,

Diameter = 10 light year

Orbital speed = 180 km/s

Suppose determine the mass of the massive object at the center of the Milky Way galaxy.

Take the distance of one light year to be 9.461×10¹⁵ m. I was able to get this it is 4.26×10³⁷ kg.

We need to calculate the radius of the orbit

Using formula of radius

r=\dfrac{d}{2}

r=\dfrac{15\times9.461\times10^{15}}{2}

r=7.09\times10^{16}\ m

We need to calculate the mass of the massive object at the center of the Milky Way galaxy

Using formula of mass

M=\dfrac{v^2r}{G}

Put the value into the formula

M=\dfrac{(180\times10^3)^2\times7.09\times10^{16}}{6.67\times10^{-11}}

M=3.44\times10^{37}\ Kg

Hence, The mass of the massive object at the center of the Milky Way galaxy is 3.44\times10^{37}\ Kg

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4 0
3 years ago
An RLRL circuit with with a 1212-ΩΩ resistor and a 0.06−H0.06−H inductor carries a current of 1A1A at t=0t=0, at which time a vo
tankabanditka [31]

Answer:

The equation of current is I=0.86 cos \left (120 t + \frac{\pi}{2}  \right )

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Compare with the standard equation,

E=E_{0}cos (2\pi ft)

2\pi ft = 120 t \\\\\\w = 2\pi f = 120 rad/s

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The impedance of the circuit is

Z =\sqrt{12^2+7.2^2}\\\\Z = 14 ohm

The current leads  by 90degree so the equation of current is

I=\frac{Eo}{Z} cos \left (120 t + \frac{\pi}{2}  \right )\\\\I=\frac{12}{14} cos \left (120 t + \frac{\pi}{2}  \right )\\\\I=0.86 cos \left (120 t + \frac{\pi}{2}  \right )

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