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Oksi-84 [34.3K]
3 years ago
6

For Other Than One And Two Family Dwellings, When Building A New Electrical Service At Least One 125 Volt, Single Phase, 15 Or 2

0 Ampere Rated Receptacle Outlet Shall Be Located Within At LEAST ________ Feet Of The Electrical Service Equipment.
Physics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer and Explanation

It was initially specified that the receptacle outlet to be located within 50 ft of the electrical service equipment.

As well, instead of the receptacle being required within 50 ft., it is now required within 25 ft. of the service. This was to accommodate the typical 25 ft. cord used by many service electricians.

The rules apply to indoor service locations other than one-and two-family dwellings. For these locations, at least one 125-volt, single-phase, 15- or 20-ampere receptacle outlet must be installed in an accessible location within 25 ft. of the indoor electrical service equipment. The receptacle must be within the same room or area as the actual service equipment.

Having a maintenance receptacle near the electrical service allows for testing, servicing and connection of portable electrical data acquisition equipment for analyzing the electrical system.

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A steel marble with 0.05 kg of mass starts from rest and rolls down a ramp. It travels 0.25 m in 1.2 seconds. Find the force act
emmasim [6.3K]

After finding acceleration, it is found that 0.02 N of force is acting on the marble

<h3>What is Force ?</h3>

Force can simply be defined as a pull or push. It is the product of mass and acceleration of the object. It is a vector quantity and it is measured in Newton.

Given that a steel marble with 0.05 kg of mass starts from rest and rolls down a ramp. It travels 0.25 m in 1.2 seconds.

The parameters to consider are;

  • m = 0.05 Kg
  • u = 0
  • s = 0.25 m
  • t = 1.2 s
  • a = ?
  • F = ?

Before we find the force acting on the marble, let us first find the acceleration by using the formula: s = ut + 1/2at²

Substitute all the parameters into the formula

0.25 = 0 + 1/2 × a × 1.2²

0.25 = 1/2 × a × 1.44

0.25 = 0.72a

a = 0.25/0.72

a = 0.35 m/s²

The force acting on the marble will be ;

F = ma

F = 0.05 × 0.35

F = 0.017

F = 0.02 N

Therefore, the force acting on the marble is 0.02 N

Learn more about Force here: brainly.com/question/388851

#SPJ1

3 0
1 year ago
A person is initially driving a car east down a straight road. the magnitude of the instantaneous acceleration is decreasing wit
Alexxandr [17]
By definition, acceleration is the change in velocity per change of time. As time passes by, the time increases in value. So, when the acceleration is decreasing while the time is increasing, then that means that the change of velocity is also decreasing with time. So, optimally, the initial velocity and the velocity at any time are very relatively close to each other,
4 0
3 years ago
Read 2 more answers
If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in m
algol [13]

Answer:

Height, H = 25.04 meters

Explanation:

Initially the ball is at rest, u = 0

Time taken to fall to the ground, t = 2.261 s

Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

H=ut+\dfrac{1}{2}at^2

Here, a = g

H=\dfrac{1}{2}gt^2            

H=\dfrac{1}{2}\times 9.8\times (2.261)^2

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.

7 0
3 years ago
An Earth satellite is orbiting at a distance from the Earth's surface equal to one Earth radius (4 000 miles). At this location,
Taya2010 [7]

Answer:0.25 times

Explanation:

Given

Distance of satellite from earth surface=Radius of earth

Force on the satellite is F=mg'

where g'=acceleration due to gravity at that point

Distance from center of Earth=R+R=2R

Gravitational Force is given by

F=\frac{GM_1M_2}{r^2}

Force F=mg'=\frac{GMm}{4R^2}-----1

Force on earth surface F=mg=\frac{GMm}{R^2}------2

Divide 1 and 2 we get

\frac{g'}{g}=\frac{R^2}{4R^2}

g'=\frac{g}{4}  

7 0
3 years ago
Which best describes friction in the context of newton's laws?
Pie

Answer:

b

Explanation:

friction needs two objects

the two objects need to touch each other

the two objects need to either have relative movement or, tend to have relative movement urge. (kinetic friction or static friction)

5 0
4 years ago
Read 2 more answers
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