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Neko [114]
3 years ago
6

23692U = 14456Ba + 89 36Kr + 3n  is a

Physics
1 answer:
alekssr [168]3 years ago
5 0
I think The answer is c
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Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb
Maslowich

Answer: 58,045,522,878.8 meters

Explanation:

Ok, the data we have is

Period = T = 88 days

Radial acceleration = ar = 3.96x10^-2 m/s^2

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ar = v^2/r = r*w^2

Where v is the velocity. r is the radius and w is the angular velocity.

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Hope this helps.

r3t40

3 0
3 years ago
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