23692U = 14456Ba + 89 36Kr + 3n is a
1 answer:
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The change in momentum of the car is 6000 kg m/s
Explanation:
According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on the object, therefore:
where
is the change in momentum
I is the impulse exerted
For the car in this problem, the impulse received is
I = 6000 kg m/s (in the forward direction)
Therefore, the change in momentum of the car is equal to this value:
(in the forward direction)
We can also calculate what is the new momentum of the car. In fact, the initial momentum is
And so, the new momentum is
Learn more about impulse and momentum:
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Answer:
The resultant force on charge 3 is Fr= -2,11665 * 10^(-7)
Explanation:
Step 1: First place the three charges along a horizontal axis. The first positive charge will be at point x=0, the second negative charge at point x=10 and the third positive charge at point x=20. Everything is indicated in the attached graph.
Step 2: I must calculate the magnitude of the forces acting on the third charge.
F13: Force exerted by charge 1 on charge 3.
F23: Force exerted by charge 2 on charge 3.
K: Constant of Coulomb's law.
d13: distance from charge 1 to charge 3.
d23: distance from charge 2 to charge 3
Fr: Resulting force.
q1=+2.06 x 10-9 C
q2= -3.27 x 10-9 C
q3= +1.05 x 10-9 C
K=9-10^9 N-m^2/C^2
d13= 0,20 m
d23= 0,10 m
F13= K * (q1 * q3)/(d13)^2
F13=9,7335*10^(-8) N
F23=K * (q2 * q3)/(d23)^2
F23= -3,09 * 10^(-7)
Step 3: We calculate the resultant force on charge 3.
Fr=F13+F23= -2,11665 * 10^(-7)
