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3 years ago

Use the figure to help you find the weight (Fg) of the body if the tension in both wires is 3.7 newtons.

Physics

2 answers:

PolarNik [594]3 years ago

7 0

Answer: 3.36 N

Explanation:

The weight of the body acting downwards is balanced by the sine components of the tension acting in the upward direction. The cosine components balance each other.

We just have to find weight, so will calculate only sine component.

Fg = 2 T sin θ

T = 3.7 N

θ = 27°

⇒ Fg = 2 × 3.7 N × sin 27° = 3.36 N

Thus, the body held by two wires having tension 3.7 N suspended from a rigid support at an angle 27° has weight = 3.36 N

topjm [15]3 years ago

4 0

I'm not completely sure, but I think it's 3.4 newtons. I hope you get it correct.

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A 1.60 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1

bija089 [108]

Answer:

Part a)

$\rho = 1.35 \times 10^{-5}$

Part b)

$\alpha = 1.12 \times 10^{-3}$

Explanation:

Part a)

Length of the rod is 1.60 m

diameter = 0.550 cm

now if the current in the ammeter is given as

$i = 18.7 A$

V = 17.0 volts

now we will have

$V = I R$

$17.0 = 18.7 R$

R = 0.91 ohm

now we know that

$R = \rho \frac{L}{A}$

$0.91 = \rho \frac{1.60}{\pi(0.275\times 10^{-2})^2}$

$\rho = 1.35 \times 10^{-5}$

Part b)

Now at higher temperature we have

$V = I R$

$17.0 = 17.3 R$

R = 0.98 ohm

now we know that

$R = \rho \frac{L}{A}$

$0.98 = \rho' \frac{1.60}{\pi(0.275\times 10^{-2})^2}$

$\rho' = 1.46 \times 10^{-5}$

so we will have

$\rho' = \rho(1 + \alpha \Delta T)$

$1.46 \times 10^{-5} = 1.35 \times 10^{-5}(1 + \alpha (92 - 20))$

$\alpha = 1.12 \times 10^{-3}$

Answer:

Part a)

$i = 1.55 A$

Part b)

$v_d = 1.4 \times 10^{-4} m/s$

Explanation:

Part a)

As we know that current density is defined as

$j = \frac{i}{A}$

now we have

$i = jA$

Now we have

$j = 1.90 \times 10^6 A/m^2$

$A = \pi(\frac{1.02 \times 10^{-3}}{2})^2$

so we will have

$i = 1.55 A$

Part b)

now we have

$j = nev_d$

so we have

$n = 8.5 \times 10^{28}$

$e = 1.6 \times 10^{-19} C$

so we have

$1.90 \times 10^6 = (8.5 \times 10^{28})(1.6 \times 10^{-19})v_d$

$v_d = 1.4 \times 10^{-4} m/s$

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4 years ago

According to Newton’s Second Law of Motion, an object will accelerate if which kind of force is applied?

Kobotan [32]

Answer:

unbalanced force

Explanation:

this is a guess so just look it up

7 0

3 years ago

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Which of Galileo’s discoveries were later used in Newton’s laws?

Mrrafil [7]

Answer:

a moving object will keep moving if not stopped

the sun being at the center of the solar system

Explanation:

Galileo is known for being the first person make a telescope, there fore being the first person to see that the sun is in the center of the solar system. he also came up with the theory that if something is pushed, it would keep moving until stopped by another force. For example, say you drop your pencil, it keeps falling until it hits the ground. That is exactly what Galileo did in his Leaning Tower of Pisa experiment and found that theory to be true.

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3 years ago

Why do polar compounds tend to have higher melting points than nonpolar compounds

I am Lyosha [343]

Answer:

The inter-molecular forces holding non-polar compounds together is low compare to that of polar compounds. Therefore, it will take less energy to break the bond for non-polar compounds and vice versa. That is why polar compounds have higher melting points than non-polar compounds.

Explanation:

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3 years ago

One circuit contains only an ac generator and a resistor, and the rms current in this circuit is IR. Another circuit contains on

snow_tiger [21]

Answer:

1/3 times.

Explanation:

Let V₀ be the peak voltage .

IR ( rms ) = ( V₀ / √2 R )

R is value of resistance

IC = ( V₀ ωC / √2 )

( 1 / ωC is reactance of capacitance in ac circuit )

$\frac{I_R}{I_C} =\frac{\frac{V_0}{\sqrt{2}R } }{\frac{V_0\omega C}{\sqrt{2} } }$

= $\frac{I_R}{I_C} = \frac{1}{\omega C R}$

When frequency is tripled angular frequency will also be tripled

hence the ratio $\frac{I_R}{I_C}$ becomes 1/3 times.

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3 years ago