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masha68 [24]
2 years ago
7

At 8:00 am, the temperature in the earth science room was measured to be 62 degrees Fahrenheit. By 12:00 pm, the temperature had

risen to 70 degrees Fahrenheit. Calculate the rate of change.
Physics
1 answer:
mash [69]2 years ago
3 0

Rate of change = (amount of change) / (time for the change)

Amount of change = (temp at the end) minus (temp at the beginning)

Amount of change = (70°F) minus (62°F) = 8°F

Time for the change = (time at the end) minus (time at the beginning)

Time for the change = (1200 - 0800) = 4 hours

Rate of change = (8°F) / (4 hours)

Rate of change = 2°F  per hour

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For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length,  the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

<h3>What is the electric field intensity 20cm away from the rod along its perpendicular bisector?</h3>

Generally, the equation for the  initial electric field intensity   is mathematically given as

dEp=\int{kd/r}cosd\theta

Therefore

e1=kd/r{sin\theta2+sinR1}

Hence

E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2

E1=B*9*10^{13})/(10*110)*\sqrt{2}

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

Read more about Electric field

brainly.com/question/9383604

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Two hockey pucks with mass 0.1 kg slide across the ice and collide. Before the collision, puck 1 is going 13 m/s to the east and
ohaa [14]

Answer:

13 m/s east

Explanation:

We can solve the problem by using the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision:

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where

m = 0.1 kg is the mass of each puck

u1 = +13 m/s is the initial velocity of puck 1

u2 = -18 m/s is the initial velocity of puck 2 (here I assume the west direction to be the negative direction, so I put a negative sign)

v1 = -18 m/s is the final velocity of puck 1

v2 = ? is the final velocity of puck 2

Simplifying m from the formula and substituting the data, we can find the final velocity of puck 2, v2:

v_2 = u_1 + u_2 - v_1 = +13 m/s + (-18 m/s) - (-18 m/s) = +13 m/s

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According to Newton's 3rd law, for every force applied, there's an equal and opposite force that will occur. So when you are walking , you are pushed forward but the plain is "pushed back" from the force

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