Need help with algebra two graphing

Is the area is 49 what is the radius and diameter of the circle

Sholpan [36]

Answer:

≈ 7.80

Step-by-step explanation:

5 0

3 years ago

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Solve the quadratic equation by completing the square. 3x2 - 6x - 4 = 0

lakkis [162]

Answer:

The solutions are

$x=1+\sqrt{\frac{7}{3}}$

$x=1-\sqrt{\frac{7}{3}}$

Step-by-step explanation:

we have

$3x^{2}-6x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$3x^{2}-6x=4$

Factor the leading coefficient

$3(x^{2}-2x)=4$

Complete the square. Remember to balance the equation by adding the same constants to each side

$3(x^{2}-2x+1)=4+3$

$3(x^{2}-2x+1)=7$

Rewrite as perfect squares

$3(x-1)^{2}=7$

$(x-1)^{2}=\frac{7}{3}$

square root both sides

$x-1=(+/-)\sqrt{\frac{7}{3}}$

$x=1(+/-)\sqrt{\frac{7}{3}}$

$x=1+\sqrt{\frac{7}{3}}$

$x=1-\sqrt{\frac{7}{3}}$

4 0

3 years ago

When does the net area of a region equal the area of a region? when does the net area of a region differ from the area of a re

stepan [7]

Before answering this question let us know what are net and total areas.

$\text{Net area}= \text{total area above x-axis}-\text{total area below x-axis}$

$\text{Total area}= |\text{total area above x-axis}|+|\text{total area below x-axis}|$

Now let us look at first part of our question. Net area of our region will be equal to total area of region when the whole region lies above x axis because then our whole region is positive.

The net area of a region will differ from the total area of the region when some part of our region is above x-axis and some part of region is below x-axis. This is because we have to subtract area of region which is below x-axis from area above x-axis to get net area.

7 0

3 years ago

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2<br> Solve the equation for b. *<br> (50 Points)<br> 12 = 6 (8) + b<br> Enter your math answer

Artemon [7]

Answer:

B=-36

Step-by-step explanation:

First, do 6(8), which equals 48

The you subtract 48 from both sides, which leaves you with:

-36=B

8 0

3 years ago

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Plssss help what is x

makvit [3.9K]

Answer:

x = 4

Step-by-step explanation:

If you do not want to read the explanation go the the next part in bold

Ok so the shorter leg of the triangle is a radius of the circle. ( This is indicated by the point in the middle of the circle.) for the hypotenuse we are given one part of the length (2) The other part also happens to be a radius ( remember that a radius is a line that starts from the center of the triangle to any point of the circumference. ) Also remember that the radius is equal to 3. That being said the hypotenuse = 2+3 which equals 5.

This triangle then happens to be a right triangle. ( A triangle formed by a tangent line and a radius is a right triangle.) This means that we can use the Pythagorean theorem to solve for x.

Below here is where the work is shown

a² + b² = c². where a and b = legs and c = hypotenuse. We are given the hypotenuse (5) and a leg (3) So we plug in what we are given and solve for the missing information. 5² = 3² + b²

5² = 25

3² = 9

we would then have 25 = 9 + b²

Next we subtract 9 from each side

25 - 9 = 16

9 - 9 cancels out

Now we have 16 = b²

finally we want to get rid of the ²

To do so we take the square root of each side

$\sqrt{16}=4\\\sqrt{b^2}=b\\b = 4$

we're left with b = 4 which means that x = 4

8 0

3 years ago