Answer:
#include <iostream>
#include <map>
using namespace std;
int main()
{
map<int, int> numbers;
cout << "Enter numbers, 0 to finish" << endl;
int number;
while (true) {
cin >> number;
if (number == 0) break;
numbers[number]++;
}
for (pair<int, int> element : numbers) {
std::cout << element.first << ": occurs " << element.second << " times" << std::endl;
}
}
Explanation:
One trick used here is not to keep track of the numbers themselves (since that is not a requirement), but start counting their occurrances right away. An STL map< > is a more suitable construct than a vector< >.
Answer:
b. lw $t4, 4($t0)
c. add $t3, $t5, $t4
Explanation:
Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.
Answer:
This is a python program that counts the number of divisors of a given number and calculates the sum of the divisors.
Explanation:
The first line defines a function "sum_divisors" with an argument "n". The square root of the argument is converted to integer and assigned to the variable "x", then a for loop is used to iterate through the range 2 to the calculated nth number of divisors in the argument.The return keyword returns the sum value.
The function is called with several arguments and printed with the print function.
