Answer:
0.818335 ≤ p ≤ 0.86366
Step-by-step explanation:
Given that:
Sample size (n) = 1000
Positive lung cancer = 841
n(p) = 841, p(p) = 841/1000 = 0.841
n(1 - p) = 1000 - 841 = 159
1 - p = 0.159
95% confidence interval
For a 95% confidence interval : z = 1.96
P ± z√p(1-p) / n
0.841 ± 1.96 * √0.841(0.159) / 1000
0.841 - (1.96 * 0.0115636) = 0.818335344
0.841 + (1.96 * 0.0115636) = 0.863664656
0.818335 ≤ p ≤ 0.86366
60 children tickets and 190 adult tickets were sold.
<u>Step-by-step explanation:</u>
Let the no. of adult tickets sold be 'a'
Let the no. of children tickets sold be 'c'
Total tickets sold = 250
Cost of 1 children ticket = $2.5
Cost of 1 adult ticket = $4
Total money collected= $910
Given that,
a + c = 250
a = 250 - c
4a + 2.5c = 910
Substitute a value
4(250 - c) + 2.5c = 910
1000 - 4c + 2.5c = 910
1000 - 1.5c = 910
-1. 5c = -90
1.5c = 90
c = 90/1.5
c = 60
a + c = 250
a + 60 = 250
a = 190
60 children tickets and 190 adult tickets were sold.
Answer:
10 blocks
Step-by-step explanation
check the image attached, the y coordinate of his school and house are the same that is, -2 so all we have to do is check the distance between x coordinates
that is , -7 and 3
distance between school and his house = 3 - (-7) = 10 blocks
There are two plausible answers
1. <span><span>x = -3/5 = -0.600
</span><span>2.x = 7/2 = 3.500</span></span>
<span> 5 – 6x = 8x + 17
</span>⇔ 5 - 17 = 8x + 6x
⇔ -12 = 14x
⇔ x = -6/7
