Answer:
-20 m/s.
Step-by-step explanation:
The computation of the average speed is shown below:
Given that
The initial velocity of the bus, u = 20 m/s
Aceleration of the bus, -a = 8 m/s²
time of motion, t = 5 s
Now The final velocity of the bus is
v = u + at
v = 20 + (-8 × 5)
v = 20 - 40
v = -20 m/s.
For the first one it is 4n^2-4
The type of land form that Caleb most likely draws is a hill. The answer is option C- a hill.
Step-by-step explanation:
- Contour lines are <u>drawn to represent the changes in the elevation</u> which helps to know the slope of the figure drawn.
- If the contour lines are drawn close, then steeper the figure is. And more distant the lines are drawn, then less steep the figure is.
- Here, the lines seem to be likely circle in shape. The distance of the outermost contour line is 20 ft. The <u>next inner lines will have reduced values of 20 ft.</u>
- Therefore, <u>the elevation gets reduced from higher to lower points</u> which provides a diagram of a hill. Since there is no continuous high and low elevations, this cannot be a valley (a range of mountains).
- Furthermore, The contour diagram for option A and D such as creek(water stream) or shoreline will have different and mixed values of elevations that seems to be a messy structure of contour lines.
Solve for x (isolate/get x by itself)
Add 5 on both sides
Subtract 1/4x on both sides
Make the denominators the same of the fractions in order to combine them. Multiply 2 to the top and bottom of 1/4x
Multiply 8 on both sides
-16 = x
Some information is missing for #6.
#7: use sine, sin35=h/5.1, h=5.1*sin35, use a calculator, h≈2.9
#23: to find the reference angle, keep subtracting the number by 360, until the remaining difference is the smallest positive number.
1406-360-360-360=326. the reference angle is 326.
now look at the remainder, the terminal line of 326 degree is in the 4th quadrant between 270 and 360, the the reference angle is 360-326=34, the angle between the terminal line and the positive x axis. 34 is the answer.
