Answer:
28 metres
Explanation:
when the bag is about to hit the ground
potential energy = kinetic energy
where m = mass
g = acceleration due to gravity
v = speed
when you simplify the above equation and make v subject of the formular we have
where g = 9.8m/s
h = 40
Answer:
a) w = 4.24 rad / s
, b) α = 8.99 rad / s²
Explanation:
a) For this exercise we use the conservation of kinetic energy,
Initial. Vertical bar
Emo = U = m g h
Final. Just before touching the floor
Emf = K = ½ I w2
As there is no friction the mechanical energy is conserved
Emo = emf
mgh = ½ m w²
The moment of inertial of a point mass is
I = m L²
m g h = ½ (m L²) w²
w = √ 2gh / L²
The initial height h when the bar is vertical is equal to the length of the bar
h = L
w = √ 2g / L
Let's calculate
w = RA (2 9.8 / 1.09)
w = 4.24 rad / s
b) Let's use Newton's equation for rotational motion
τ = I α
F L = (m L²) α
The force applied is the weight of the object, which is at a distance L from the point of gro
mg L = m L² α
α = g / L
α = 9.8 / 1.09
α = 8.99 rad / s²
Answer: Gravity
Explanation: Gravity is pulling down on the ball, making it stay on the floor
Answer: 10m/s²
Explanation: Acceleration= (v-u)/t
So here it’s (40-20)/2
Which is equal to 10
