A thin rod (length = 1.09 m) is oriented vertically, with its bottom end attached to the floor by means of a frictionless hinge.
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Answer:
Plane will 741.6959 m apart after 1.7 hour
Explanation:
We have given time = 1.7 hr
So if we draw the vectors of a 2d graph we see that the difference in angles is =
Speed of first plane = 730 m/h
So distance traveled by first plane = 730×1.7 = 1241 m
Speed of second plane = 590 m/hr
So distance traveled by second plane = 590×1.7 = 1003 m
We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.
Using the law of cosine, representing the distance between the planes, we see that:
r = 741.6959 m
While plane is moving under tailwind condition it took time "t"
so here we will have
here net speed of the plane will be given as
similarly when it moves under the condition of headwind its net speed is given as
now time taken to cover the distance is 2 hours more
now solving two equations
solving above for v_w we got
The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.
<h3>What is uncertainty in measurement?</h3>- This is the error associated in an attempt measure the object accurately.
The percent uncertainty in measuring the light weight object is calculated as follows;
The uncertainty of the heavy object if the scale remains constant is calculated as follows;
Learn more about percent uncertainty here: brainly.com/question/5493941