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TEA [102]
3 years ago
15

The velocity of a bob on a simple pendulum at the lowest position is 10.56 m/s. What is the maximum vertical height it is able t

o rise to?
Physics
1 answer:
kondaur [170]3 years ago
7 0

um I do not know sorry

Explanation:

ummmmmmjjhfgfffff

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A person covers a distance of 320 miles in a travel time of 8 hours. What is the speed for this trip?
goldfiish [28.3K]
Take 320 and divide by 8
320/8 = 40 mi/hr or A
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How much farther from the charge is the 2000 v equipotential surface than the 3000 v surface?
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Answer:

r1 -r2 = 3.75cm

Explanation:

Check the attached file for the solution

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Explain how the pressure at the bottom of a container depends on the container shape and the fluid height
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The pressure at the bottom of a column of fluid in a container
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During a goal-line stand, a 112-kg fullback moving eastward with a speed of 6 m/s
11111nata11111 [884]

Answer:

-1.24 m/s

Explanation:

Total momentum before collision = total momentum after collision

Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).

Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back  6 m/s (east), velocity of line back = -8 m/s (west). Hence:

Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s

The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.

Let velocity after collision be v, hence:

The total momentum after collision = (112 + 120)v = 232v

Total momentum before collision = total momentum after collision

-288 = 232v

v = -288 / 232

v = -1.24 m/s

Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).

7 0
3 years ago
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