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TEA [102]
3 years ago
15

The velocity of a bob on a simple pendulum at the lowest position is 10.56 m/s. What is the maximum vertical height it is able t

o rise to?
Physics
1 answer:
kondaur [170]3 years ago
7 0

um I do not know sorry

Explanation:

ummmmmmjjhfgfffff

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Kellie jogs 6.0 km in 54 minutes, then 1.0 km in 16 minutes. What is her average speed in km/min please show your work
satela [25.4K]

Answer:

Vprom = 0.00347[km/min]

Explanation:

We can calculate each of the average speeds and then perform the overall average between the two speeds.

V1 = 6/54

V1 = 0.111[km/min]

V2 = 1/16

V2 = 0.0625[km/min]

V_{prom} = \frac{V_{1} + V_{2}}{2}  \\V_{prom} = \frac{0.1111 + 0.0625}{2}\\V_{prom} = 0.00347 [km/min]

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Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. Th
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In order to calculate the weight, we may simply use:
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The sum of the reaction force and the upward component of child pulling will be equal to total downward force. The force acting downwards is the weight. Therefore:
R + 12sin(45) = 294.3
R = 285.82 N

The acceleration can be found using the resultant force and the mass of the sled. The resultant force is:
F(r) = pulling force + pushing force - friction
F(r) = 12cos(45) + 8 - 5
F(r) = 11.48 N
a = F/m
a = 11.48 / 30
a = 0.38 m/s²
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