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3 years ago

15

The velocity of a bob on a simple pendulum at the lowest position is 10.56 m/s. What is the maximum vertical height it is able t

o rise to?

1 answer:

kondaur [170]3 years ago

7 0

um I do not know sorry

Explanation:

ummmmmmjjhfgfffff

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Five locations are marked on the world map. Which location is most prone to hurricanes?

Kruka [31]

Answer: A is the spot that is prone to hurricane mostly.

Explanation:

The locations on the world map spot A, B, C, D, E are regions with country prone to hurricane.

The SPOT A, is GULF of Mexico, an ocean basin closer to the Atlantic ocean, surrounded with the North American continent, the Hawaiian island is also within that region.

The SPOT B, is the southern Pacific ocean with countries like BRAZIL, PERU, ECUADOR, CHILE, in that same region. This is also visited by the hurricane.

The SPOT C, is within the regions of AFRICA, countries at the edge are also affected by hurricane.

The SPOT D, is Asian continent with Russia at the edge. They are also prone to hurricane.

The SPOT E, is the North Pacific ocean region located at the top left hand side of the world map, with countries like Canada, Alaska and co. Close to the artic circle.

With the observation of all this spot, THE SPOT A, is most prone to hurricane, and its effect are very high there....

Country thee are greatly affected by it,

3 0

3 years ago

Read 2 more answers

In an insulated container, 0.50 kg of water at 80°C is mixed with 0.050 kg of ice at −5.0°C. After a while, all the ice melts, l

Phoenix [80]

Explanation:

When ice tends to absorb heat energy then it will change into liquid state. Now, change in the temperature of cold water $dT = T_{f} - 0^{o}C$ = $T_{f}$

Change in the temperature of original water in the container $dT' = 80 -T_{f
}$

Latent heat of melting of ice L = 80 cal/g

Specific heat of water C = 1 cal/g C

Heat absorbed by ice to melt = mass( $m_{i}$ ) x latent heat(L)

Heat absorbed by water = mass( $m_{w}$ ) x specific heat(C) x change in temperature (dT')

$m_{i}$ = 0.050 kg = 50 g and $m_{w}$ = 0.50 kg = 500 g

Now, heat lost by water is as follows.

heat lost by hot water( at $80^{o}C$ ) = heat absorbed by the ice + heat absorbed by cold water

$m_{i} \times L + m_{i} \times C dT = m_{w} \times C dT'$

$50 \times 80 + 50 \times 1 \times (T_{f}) = 500 \times 1 \times (80 - T_{f})$

So, we will cancel out 50 from each term given above. Hence,

$80 + T_{f} = 800 - 10T_{f}$

$11 T_{f}$ = 720

$T_{f} = 65.45^{o}C$

Thus, we can conclude that final temperature of the water is $65.45^{o}C$ .

6 0

3 years ago

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A piston–cylinder assembly contains 5.0 kg of air, initially at 2.0 bar, 30 oF. The air undergoes a process to a state where the

vladimir2022 [97]

Answer:

The work and heat transfer for this process is = 270.588 kJ

Explanation:

Take properties of air from an ideal gas table. R = 0.287 kJ/kg-k

The Pressure-Volume relation is <em>PV</em> = <em>C</em>

<em>T = C </em> for isothermal process

Calculating for the work done in isothermal process

<em>W</em> = <em>P</em>₁<em>V</em>₁ $ln[\frac{P_{1} }{P_{2} }]$

= <em>mRT</em>₁ $ln[\frac{P_{1} }{P_{2} }]$ [∵<em>pV</em> = <em>mRT</em>]

= (5) (0.287) (272.039) $ln[\frac{2.0}{1.0}]$

= 270.588 kJ

Since the process is isothermal, Internal energy change is zero

Δ<em>U</em> = $mc_{v}(T_{2} - T_{1} ) = 0$

From 1st law of thermodynamics

Q = Δ<em>U </em>+ <em>W</em>

= 0 + 270.588

= 270.588 kJ

4 0

3 years ago

Critical thinking requires that _______.

stiks02 [169]

Conclusions be adjusted as necessary to incorporate new knowledge.

Hope this helps =)
im taking an integrated physics and chemistry test rite now!

5 0

3 years ago

How does the wind reversing make the tempurature change asap pls

OlgaM077 [116]

Answer:

Because the difference in air temperature of neighbouring air masses causes the wind to blow. Warmer air is less dense, so colder air subsides into the space occupied by the warmer air due to the force of gravity, displacing the warmer air upwards. This is fundamentally the reason temperature change may be accompanied by wind. It is possible to think of situations where only one of these effects is observed at any one place, due to the large size or stationary nature of atmospheric boundary phenomena.

Explanation:

3 0

2 years ago

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