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Aliun [14]
3 years ago
11

During a certain period of time, a car can cover the distance of 120 miles, going at an average speed of 55 mph. What distance o

ver the same period of time would cover a truck, going at an average speed of 44 mph?
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0
Remember that distance equals rate multiplied by time, or put more compactly, d=rt

Here, we're looking for the distance traveled by a truck, given only its rate, 44 mph. We're also given that both of the vehicles travel for is the same. This lets us use the car's information to find that time, which we can then use to find the distance traveled by the truck.

For the car, our distance is 120 miles, our rate is 55 mph, and our time is unknown; let's call that value t. We have:

120=55t

Dividing both sides by 55, we find:

\frac{120}{55}=t\\\\ \frac{24}{11}=t

So our time is 24/11 hours - roughly 2 hours and 13 minutes. We'll use the 24/11 value to get as exact an answer as we can, though.

For the truck, we know its rate and its time (24/11 hours), but we don't know its distance. We'll call it d. Putting in our new value for time, we have:

d=44 \big(\frac{24}{11}\big) \\
d=4(24)\\
d=96

So, in 24/11 hours, the truck will have traveled 96 miles traveling at its average speed.
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150% of what number is 186
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1 year ago
Gwen volunteered to work at the ticket booth for her school's Halloween carnival. The chart below gives the number of hours Gwen
n200080 [17]

A linear relation is a relationship between two variables that when the corresponding pair of values of the variables are plotted, a straight line is obtained

The equation for the relationship between hours Gwen worked and number of tickets is <u> t = </u><u>15·h</u>

<u />

The reason the above equation is correct is as follows:

The given parameters are;

The table of values;

Hours(h): 1, 2, 3, 4

Tickets (t): 15, 30, 45, 60

Required: To write an equation that gives the relation between the number of hours Gwen worked and the number of tickets sold

Solution:

From the given table, we have;

The common difference between successive <em>h-values </em>is 1

The <em>common difference</em> between successive t<em>-values </em>is 30 - 15 = 45 - 30 = 60 - 45 = 15 = Constant

Given that the common difference of the <em>h</em>, and <em>t-values</em> are constant, the relationship is a linear relationship of the form, t = m·h + c

Where;

m = The rate of change of <em>t</em> with <em>h</em>, as follows;

m = (30 - 15)/(2 - 1) = 15

∴ t - 15 = 15 × (h - 1)

t - 15 = 15·h - 15

t = 15·h - 15 + 15 = 15·h

t = 15·h

The equation for the relation between the number of hours Gwen worked and the number of tickets she sold is<u> t = </u><u>15·h</u>

<u />

Learn more about mathematical relationships here:

brainly.com/question/10185505

brainly.com/question/18936577

brainly.com/question/11391605

7 0
2 years ago
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