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bogdanovich [222]
3 years ago
13

Select all that applies!

Mathematics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

C.

Step-by-step explanation:

Because there is constant term 4 in the question, but there is no any such constant term in the given options.

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Given: AD = BC and AD || BC
o-na [289]

Answer:

See below

Step-by-step explanation:

<u><em>Proof:</em></u>

<u><em>Statements  </em></u>                                  |  <u><em>Reasons</em></u>

AD ≅ BC                                         | Given

AD ║ BC                                         | Given

AC ≅ AC                                         |  Reflexive Property

∠DAC ≅ ∠ACB                               | If 2 || lines are cut by a trans., the                                                                       |  alternate interior ∠s are congruent.

ΔADC ≅ ΔBCA                               | S.A.S  Postulate

BA ≅ DC                                         | Corresponding sides of congruent Δs

So, quad. ABCD is a ║gm             | If a quad. has its opposite sides

                                                       | congruent, the quad. is a parallelogram.

5 0
3 years ago
A factory makes an oil mixture by mixing oils of grades A and B as follows. For every 2.3 liters of grade A oil, 1.2 liters of g
lozanna [386]
<span>To produce 1000L of mixture the factory will need 657 liters of grade A and 343 liters of grade B. To determine this you have to figure out the percentage of each grade in the mixture. The ratio is 2.3 liters to 1.2 liters. Therefor in this scenario the unit equaling 100% is 3.5 liters. To find the percentage of grade A you divide the amount used by the total amount of the unit 100%: 2.3 divided by 3.5 = .657 (multiply the answer by 100 to get 65.7%). To find the percentage of grade B you divide the amount used by the total amount of the unit 100%: 1.2 divided by 3.5 = .343 (multiply the answer by 100 to get 34.3%) To test your answer make sure both percentages add up to 100%: 65.75 plus 34.35 = 100% To determine how much of grade A and grade B is needed for a set amount of liters you multiply the percentage by the liters needed. For this situation you multiply 65.7% (when multiplying percentages you need to multiply in decimal form). For grade A you multiply .657 (65.7%) by 1000 liters = 657 liters For grade B you multiply .343 (34.3%) by 1000 liters = 343 liters To test your answer you can use the same addition as you did to test the percentages: 657 liters plus 343 liters = 1000 liters</span>
4 0
4 years ago
Read 2 more answers
What is the following quotient? 5/ sqrt 11 - sqrt 3
nasty-shy [4]

 

\displaystyle\\\frac{5}{\sqrt{11}-\sqrt{3}}=?\\\\\\\text{We rationalize the denominator.}\\\\\frac{5}{\sqrt{11}-\sqrt{3}}=\frac{5(\sqrt{11}+\sqrt{3})}{(\sqrt{11}-\sqrt{3})(\sqrt{11}+\sqrt{3})}=\frac{5(\sqrt{11}+\sqrt{3})}{(11-3)}=\boxed{\bf\frac{5\sqrt{11}+5\sqrt{3})}{8}}

3 0
4 years ago
Read 2 more answers
What is ( 2 ^8 x 5^-5 x 19^0) ^-2 x ( 5^-2 / 2^3 ) ^4 x 2^28
Lera25 [3.4K]

(2^8x5^-5x19^0)^-2 x (5^-2/2^3)^4 x 2^28

(256x0.00032x1)^-2 x (0.04/8)^4 x 2^28

0.08192^-2 x 0.005^4 x 268,435,456

149.0116119384766 x 0.000000000625 x 268,435,456

0.000000093132257 x 268,435,456

= 25

7 0
3 years ago
Help needed! Trying to get answer
Angelina_Jolie [31]
1/27 and (3^15)*(3^-18)
4 0
3 years ago
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