Ask question

Ask question

All categories

3 years ago

7

Perpendicular lines form angles

1 answer:

4vir4ik [10]3 years ago

3 0

What is the question?

You might be interested in

You buy 60 of your favorite songs from a Web site that charges $0.99 for each song. What is the cost of 60 songs? Use mental m

castortr0y [4]

Answer:

$59.4

Step-by-step explanation:

Round up: 60*1 = $60. Everytime you add $0.99, you subtract off a penny, so you will subtract off 60 pennies. 60 cents from the original answer, so 60-0.6=59.4.

7 0

3 years ago

3(2b-4a+3c) if a =1/2,b=3, and c=-2/3

valentina_108 [34]

This is just substitution. so 3(2(3)-4(1/2)+3(-2/3)= 3(6-2-2)= 3(2) = 6. Basically you plug in the values they gave you for the variables and then just solve one step at a time

8 0

3 years ago

Read 2 more answers

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago

24% of students in a class are girls. If there are less than 30 students in this class, how many students are there? How many gi

castortr0y [4]

Answer:

Step-by-step explanation:

The GCF (greatest common factor) of 24 and 30 is 6.

30-30/6=25

25 students in the class

24% of 25 is 6

6 girls in the class

5 0

2 years ago

Please help me with this problem

nadya68 [22]

Which Problem Do You Need Help With?

7 0

3 years ago