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4 years ago

What characteristics determine how easily two substances change temperature? Check all that apply.

1 answer:

4 0

amount of time the two substances are in contact. area in contact between the two substances. specific heat of the material that makes up the substances. the density of the two substances in contact.

You might be interested in

A solution has a pH of 2.5. what is the H+

romanna [79]

Answer: The concentration of $H^+$ in the solution is $3.16\times 10^{-3}M$

Explanation:

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.

$pH=-\log [H^+]$ .....(1)

We are given:

pH of solution = 2.5

Putting values in equation 1, we get:

$2.5=-\log [H^+]$

$[H^+]=10^{-2.5}$

$[H^+]=3.16\times 10^{-3}M$

Hence, the concentration of $H^+$ in the solution is $3.16\times 10^{-3}M$

4 0

3 years ago

How many moles of NO2 form when 63.25 g N2O5 decompose? 2N₂O54NO₂ + O₂

KonstantinChe [14]

Answer:

1.1713 moles

Explanation:

RFM of N2O5=108

Moles of N2O5= mass/RFM= 63.25/108=0.5856 moles

Mole ratio of N2O5:NO2= 2:4

Therefore moles of NO2= 4/2*0.5856= 1.1713 moles

4 0

2 years ago

How do you find out how many protons,electrons, and neutrons an atom has?

Evgen [1.6K]

So the atomic number is the same as protons, and electrons and to get neutrons by subtracting number of protons from atomic mass.

8 0

3 years ago

A sealed plastic bag is filled with 1 l of air and has a pressure of 101.3 kpa. You sit on the bag and the pressure increases to

sesenic [268]

Answer:

The answer to your question is V2 = 0.203 kPa

Explanation:

Data

Volume 1 = V1 = 1l

Pressure 1 = P1 = 101.3 kPa

Volume 2= V2 = ?

Pressure 2 = 500 kPa

Process

- Use the Boyle's law to solve this problem

P1V1 = P2V2

-Solve for V2

V2 = P1V1/P2

-Substitution

V2 = (101.3 x 1) / 500

-Simplification

V2 = 101.3 / 500

-Result

V2 = 0.203 kPa

8 0

4 years ago

How many grams of sodium formate, NaCHO2, would have to be dissolved in 3.0 L of 0.12 M formic acid (pKa 3.74) to make the solut

kolbaska11 [484]

Answer:

$Mass_{sodium\ formate}= 889.57\ g$

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the acidic buffer solution as:

$pH=pK_a+log\frac{[salt]}{[acid]}$

Given that:-

[Acid] = 0.12 M

Volume = 3.0 L

pKa = 3.74

pH = 5.30

So,

$5.30=3.74+log\frac{[sodium\ formate]}{0.12}$

Solving, we get that:-

[Sodium formate] = 4.36 M

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

So,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

So, Moles of sodium formate = 4.36*3.0 moles = 13.08 moles

Molar mass of sodium formate = 68.01 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$13.08\ mole= \frac{Mass}{68.01\ g/mol}$

$Mass_{sodium\ formate}= 889.57\ g$

5 0

4 years ago