Question

Given the equation representing a reversible reaction:

Answer 1

Answer:

- Acetic acid (CH₃COOH) and hydronium ion (H₃O⁺)

Explanation:

Hello,

In this case, based on the acid-base theory which states that acids are known as H⁺ donors, if we consider the direct reaction:

$CH_3COOH(aq) + H_2O \rightarrow CH_3COO^-(aq) + H_3O^+(aq)$

It is clear that the acetic acid is the first H⁺ donor as it losses one H⁺ to turn into the acetate ion. Moreover, if we consider the inverse reaction:

$CH_3COO^-(aq) + H_3O^+(aq)\rightarrow CH_3COOH(aq) + H_2O$

It is also clear that the hydronium ion is the second H⁺ donor as it losses one H⁺ to turn into water.

Best regards.