Answer:
If the terms of a polynomial do not have a GCF, does that mean it is not factorable? Explain. The terms of a polynomial do not have to have a common factor for the entire polynomial to be factorable.
glad i could help
With dot plot if it’s symmetrical its the mean and MAD, so i think that.
There are 4 cats, 2 dogs and 1 goldfish for a total of 7 animals. These animals should be distributed to each of Mr. Smith's children. But we must note of the restrictions.
This is the solution for the problem:
2(7C6) + 2(7C4) + 3(7C1)
How is this so? The first term stand for Anna and Betty, hence, 2. Each of them must choose 6 out of the 7 animals (except for goldfish). That's why it's written as '7C6' which is combination of 6 out of 7. It stands for nCr, or 'r' objects out of 'n'. The equation for that is n!/[r!(n-r)!]. The second term is for Charlie and Danny who gets 4 cats out of the 7 animals. And lastly, the other 3 would get the three last pet available.
Solving the equation, the answer is 105 ways.
Area equal length time width
A = 13*8 = 104 squared meter
hope helped
Prob(first ball being blue) = 6 / (6 + 3 + 3) = 6/12 = 1/2
Prob ( picking a yellow ball) = 3 /12 = 1/4
As the 2 events are independent the probabilities are multiplied
So the answer is 1/2 * 1/4 = 1/8