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anastassius [24]
3 years ago
12

Find the IQR: (find the median, then find the median of the first group and then the next group. Now subtract big median minus t

he small median.) 20, 17, 16, 3, 7, 45
Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

13

Step-by-step explanation:

The IQR = Interquartile Range is the difference between the first and third quartile

Rearranged data set:

3, 7, 16, 17, 20, 45

Step 1

We find the first quartile = Q1

= 1/4(n + 1)th number

n = 6

= 1/4(6 + 1)th

= 1/4(7)th

= 1 3/4th number

This = 7

Step 2

We find the third quartile = Q3

= 3/4(n + 1)th number

n = 6

= 3/4(6 + 1)th

= 3/4(7)th

= 21/4th number

= 5 1/4 th number

This = 20

Step 3

IQR = Q3 - Q1

= 20 - 7

= 13

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The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and th
Alex777 [14]

Answer:

The correct option is b) 4.71

Step-by-step explanation:

Consider the provided information.

Test statistic for proportion: z=\frac{\hat p-p}{\sqrt{\frac{pq}{n}}}

It is given that the claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n=800 deaths of the elderly with 15 percent of them attribute to residential falls.

Therefore, \hat p=0.15, p = 0.1, q = 1-0.1 = 0.9 and n = 800.

Substitute the respective values in the above formula.

z=\frac{0.15-0.1}{\sqrt{\frac{0.1\times0.9}{800}}}

z=\frac{0.05}{\sqrt{\frac{0.09}{800}}}

z\approx4.71

Hence, the correct option is b) 4.71

3 0
3 years ago
Find the length of B to the nearest tenth using the Pythagorean theorem.​
bekas [8.4K]

Step-by-step explanation:

Here

BC=P=10

AC=B=b

AB=H=15

then using fourmula

h^2= p^2+ b^2

b^2= 15×15 - 10× 10

b^2= 125

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4 0
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Answer:0.32 is closer the the number one then 0.102 is

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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