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anastassius [24]

3 years ago

12

Find the IQR: (find the median, then find the median of the first group and then the next group. Now subtract big median minus t

he small median.) 20, 17, 16, 3, 7, 45

1 answer:

snow_lady [41]3 years ago

3 0

Answer:

13

Step-by-step explanation:

The IQR = Interquartile Range is the difference between the first and third quartile

Rearranged data set:

3, 7, 16, 17, 20, 45

Step 1

We find the first quartile = Q1

= 1/4(n + 1)th number

n = 6

= 1/4(6 + 1)th

= 1/4(7)th

= 1 3/4th number

This = 7

Step 2

We find the third quartile = Q3

= 3/4(n + 1)th number

n = 6

= 3/4(6 + 1)th

= 3/4(7)th

= 21/4th number

= 5 1/4 th number

This = 20

Step 3

IQR = Q3 - Q1

= 20 - 7

= 13

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r-ruslan [8.4K]

Answer:

x=−18

Step-by-step explanation:

Let's solve your equation step-by-step.

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3

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Step 1: Simplify both sides of the equation.

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Step 2: Subtract 4 from both sides.

1

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5 0

3 years ago

Read 2 more answers

One end of a line segment has the coordinates (-6,2). If

CaHeK987 [17]

Answer:

The coordinates of the other end is $(16,2)$

Step-by-step explanation:

Given

$End 1: (-6,2)$

$Midpoint: (5,2)$

Required

Find the coordinates of the other end

Let Midpoint be represented by (x,y);

(x,y) = (5,2) is calculated as thus

$(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

So

$x = \frac{x_1 + x_2}{2}$ and $y = \frac{y_1 + y_2}{2}$

Where $(x_1,y_1) = (-6,2)$ and $(x,y) = (5,2)$

So, we're solving for $(x_2,y_2)$

Solving for $x_2$

$x = \frac{x_1 + x_2}{2}$

Substitute 5 for x and -6 for x₁

$5 = \frac{-6 + x_2}{2}$

Multiply both sides by 2

$2 * 5 = \frac{-6 + x_2}{2} * 2$

$10 = -6 + x_2$

Add 6 to both sides

$6 + 10 = -6 +6 + x_2$

$x_2 = 16$

Solving for $y_2$

$y = \frac{y_1 + y_2}{2}$

Substitute 2 for y and 2 for y₁

$2 = \frac{2 + y_2}{2}$

Multiply both sides by 2

$2 * 2 = \frac{2 + y_2}{2} * 2$

$4 = 2 + y_2$

Subtract 2 from both sides

$4 - 2 = 2 - 2 + y_2$

$y_2 = 2$

$(x_2,y_2) = (16,2)$

Hence, the coordinates of the other end is $(16,2)$

3 0

3 years ago

X= <br> 5<br> 10<br> 6<br> Please help

Lerok [7]

Answer:

x = 6

Step-by-step explanation:

(segment piece) x (segment piece) = (segment piece) x (segment piece)

2*x = 3*4

2x = 12

Divide each side by 2

2x/2 = 12/2

x = 6

8 0

3 years ago

You are working for a company that creates tubes that measure 10 cm long and have a diameter of 6 cm. The tubes need to be cut j

Nataly_w [17]

Answer:

$A= 2\pi (3cm)^2 +1 2\pi (3cm)(10 cm)= 18 \pi + 60\pi = 78 \pi cm^2$

And replacing the value of $\pi =3.14$ we got:

$A = 78*3.14 cm^2= 244.92 cm^2$

Step-by-step explanation:

For this case we have the long who represent the height 10 cm and the diameter is 6cm. So then the radius is given by:

$r = \frac{D}{2}= \frac{6cm}{2}= 3cm$

And the surface area for a cylinder is given by this formula:

$A= 2\pi r^2 +2 \pi rh$

And replacing the info given we got:

$A= 2\pi (3cm)^2 +1 2\pi (3cm)(10 cm)= 18 \pi + 60\pi = 78 \pi cm^2$

And replacing the value of $\pi =3.14$ we got:

$A = 78*3.14 cm^2= 244.92 cm^2$

4 0

3 years ago

Solve for x. x+5.39>4.48

Evgesh-ka [11]

Answer:

$\boxed {x > -0.91}$

Step-by-step explanation:

Solve for $x$ :

$x + 5.39 > 4.48$

-Subtract $5.39$ on both sides:

$x + 5.39 - 5.39 > 4.48 - 5.39$

$x > -0.91$

So, therefore, the final answer is $\boxed {x > -0.91}$ .

3 0

3 years ago