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anastassius [24]
3 years ago
12

Find the IQR: (find the median, then find the median of the first group and then the next group. Now subtract big median minus t

he small median.) 20, 17, 16, 3, 7, 45
Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

13

Step-by-step explanation:

The IQR = Interquartile Range is the difference between the first and third quartile

Rearranged data set:

3, 7, 16, 17, 20, 45

Step 1

We find the first quartile = Q1

= 1/4(n + 1)th number

n = 6

= 1/4(6 + 1)th

= 1/4(7)th

= 1 3/4th number

This = 7

Step 2

We find the third quartile = Q3

= 3/4(n + 1)th number

n = 6

= 3/4(6 + 1)th

= 3/4(7)th

= 21/4th number

= 5 1/4 th number

This = 20

Step 3

IQR = Q3 - Q1

= 20 - 7

= 13

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What is the distance between the following points?
likoan [24]

Answer:

11.

Step-by-step explanation:

9 right, and 2 up

7 0
3 years ago
Please help me. these problems<br>​
jeyben [28]

Answer:

1st problem:

Converges to 6

2nd problem:

Converges to 504

Step-by-step explanation:

You are comparing to \sum_{k=1}^{\infty} a_1(r)^{k-1}

You want the ratio r to be between -1 and 1.

Both of these problem are so that means they both have a sum and the series converges to that sum.

The formula for computing a geometric series in our form is \frac{a_1}{1-r} where a_1 is the first term.

The first term of your first series is 3 so your answer will be given by:

\frac{a_1}{1-r}=\frac{3}{1-\frac{1}{2}}=\frac{3}{\frac{1}{2}=6

The second series has r=1/6 and a_1=420 giving me:

\frac{420}{1-\frac{1}{6}}=\frac{420}{\frac{5}{6}}=420(\frac{6}{5})=504.

3 0
3 years ago
Q4.
goblinko [34]

The coding of the statistic is used to make it easier to work with the large sunshine data set

  • The mean of the sunshine is 3.05\overline 6
  • The standard deviation is approximately  <u>18.184</u>

<u />

Reason:

The given parameters are;

The sample size, n = 3.

∑x = 947

Sample corrected sum of squares, Sₓₓ = 33,065.37

The mean and standard deviation = Required

Solution:

Mean, \ \overline x = \dfrac{\sum x_i}{n}

The mean of the daily total sunshine is therefore;

Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6

s = \dfrac{x}{10 } - \dfrac{1}{10}

  • E(s) = \dfrac{Ex}{10 } - \dfrac{1}{10}

E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6

  • The mean ≈ 3.05\overline 6

Alternatively

,The \ mean \  of \  the \  daily  \ total  \ sunshine,  \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6

The mean of the daily total sunshine, \overline s ≈3.05\overline 6

  • Var(s) = Var \left(\dfrac{x}{10 } - \dfrac{1}{10} \right)

Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)

Therefore;

Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537

Therefore;

  • s = \sqrt{330.6537} \approx 18.184

The standard deviation, s_s ≈ <u>18.184</u>

Learn more about coding of statistic data here:

brainly.com/question/14837870

3 0
2 years ago
Which of the following equations have infinitely many solutions?
ikadub [295]

The equation which represents a system with infinitely many solutions is;

<h3>What system of equations have infinitely many solutions as in the task content?</h3>

The condition for a situation in which case an equation has infinitely many solutions is such that the right hand side and left hand side of the equation are equal.

On this note, it follows that the answer choices which represents the equations with infinitely many solutions is;

  • 46x+23=46x+23

Read more on infinitely many solutions;

brainly.com/question/27927692

#SPJ1

4 0
2 years ago
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