Answer:
See explanation
Explanation:
When we have to write an organic molecule, we have to remember the <u>IUPAC rules.</u> In this case, we have: "2,5-dimethylfuran". We can divide the name into two parts:
<u>a) "2,5-dimethyl"</u>
<u>b) "Furan"</u>
For part a) we have the indications of the <u>"subgroups</u>" bonded to the main structure, in this case, we have 2 <u>methyl groups</u> (
) bonded to carbons 2 and 5.
For part b) we have the main, structure. In this case furan, this compound is a <u>cyclic structure</u> of 5 members in which we have in the middle of the molecule an oxygen atom and 2 double bonds (see figure 1).
Finally, when we add the methyl groups to the furan we will get the 2,5-dimethylfuran. (see figure 2).
I hope it helps!
Evidence could be gathered in the future that contradicts original theories. <span>Phenomena cannot be proven by conclusive evidence in science because, as of now, the evidence isn't conclusive. It is speculation. Just as a phenomena cannot be proven, it also cannot be disproven. </span>
you can't solve that, you need more information in that equations like and x or an y.
Otherwise, the equation stays like that.
Answer:
The stock name (CrBr3) : <em>chromium(III) sulfide</em>
The classical name (CrBr3) : <em>chromic bromide</em>
The percent composition of the compound.
A O-18.18%, N-21.21%, H-60.60%
<h3>Further explanation</h3>
Given
6.00 grams of oxygen,
7.00 grams of nitrogen,
20.00 grams of hydrogen.
Required
The percent composition
Solution
Total mass :
= mass of O + mass of N + mass of H
= 6 + 7 + 20
= 33 g
% O = 6/33 x 100%= 18.18%
% N = 7/33 x 100%=21.21%
% H = 20/33 x 100% = 60.6 %