A sample 0. 100 moles of a gas is collected at at STP . 2.24 is the volume of the gas in liters.
The STP means standard temperature and pressure.
At STP,
Temperature = 0 °C =273 K
Pressure = 1 atm
We get value of volume by using ideal gas equation,
PV = nRT
- P is the pressure of the gas = 1 atm
- V is the volume occupied by the gas = ?
- n is the number of the moles = 1 mole
- T is the temperature of the gas = 273 K or 0 °C
- R universal gas constant = 8.31 J/ mole × K
Calculation,
Since, one mole of a gas occupy 22.4 L volume at STP
So, for 0.1 mole volume occupy = 22.4L × 0.1 mole/1 mole = 2.24L
To learn more about volume at STP,
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D, forms from decomposed material
Answer:
A beaker
Step-by-step explanation:
Specifically, I would use a 250 mL graduated beaker.
A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.
You don't need precisely 100 mL solution.
If the beaker is graduated, you can easily measure 100 mL of the stock solution.
Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).
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Answer:
<em>249 kJ</em>
Explanation:
To obtain the energy change of the reaction:
H₂O → H₂ + ¹/₂ O₂
It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:
Energy of products:
1 mol of H-H bond × 436 kJ/mol = 436 kJ
¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ
Energy of reactant:
2 mol of H-O bond × 467 kJ/mol = 934 kJ
Energy change of the reaction is:
934 kJ - (436 kJ + 249 kJ) = <em>249 kJ</em>
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I hope it helps!