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2 years ago

How many tiny frogs sitting next to each other would measure the same length as a Blue Whale?

Chemistry

2 answers:

Naddik [55]2 years ago

8 0

Answer:

LOOK BELOW

Explanation:

Well a female is 82ft and a male is 79ft so we will just go with both answers. A tiny frog is about a estimate length of 0.27 inches so you would have to divide and or multiply 82 by 0.27 getting your first length then do the same with teh next one and thats you answer! hope i helped bby :3

Svetlanka [38]2 years ago

6 0

Answer:

About 2,500

Explanation:

The blue whale is the largest animal on Earth. The length of a blue whale is about 25 m, although is is said the largest confirmed measure is 29.9m.

The tiny frogs measure about 10mm.

You can estimate the number of tiny frogs that have the same length as a blue whale dividing the approximate average length of a blue whale by the approximate average length of the tiny frogs.

First convert 25m to mm:

25m × 1,000mm/m = 25,000 mm

Now, divide:

25,000mm / 10mm = 2,500

Hence, about 2,500 tiny frogs sitting next to each other would measure the same length as a blue whale.

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A sample of 10.5 g of nitrogen reacts with 20.2 g of hydrogen to produce ammonia. (36 points

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Explanation:

A. 55

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1 year ago

Ppredict the identity of the precipitate in the below reaction: BaCl2(aq) + K2SO4(aq) →

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Answer: The precipitate formed is $BaSO_4$

Explanation:

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A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.

The balanced chemical equation is:

$K_2SO_4(aq)+BaCl_2(aq)\rightarrow BaSO_4(s)+2KCl(aq)$

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2 years ago

Which scientist arranged the elements in order of increasing atomic number, rather than increasing atomic mass?

pentagon [3]

Answer:

Henry Moseley

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The present periodic law is stated as "the properties of elements are a periodic function of their atomic number".

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2 years ago

In chemical reactions, the number of atoms in the product is ________________.

irina1246 [14]

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Explanation:

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2 years ago

When 100 mL of 0.200 M NaCl(aq) and 100 mL of 0.200 M AgNO3(aq), both at 21.9 °C, are mixed in a coffee cup calorimeter, the tem

masya89 [10]

Answer:

There is 1.3 kJ heat produced(released)

Explanation:

Step 1: Data given

Volume of a 0.200 M Nacl solution = 100 mL = 0.1 L

Volume of a 0.200 M AgNO3 solution = 100 mL = 0.1 L

Initial temperature = 21.9 °C

Final temperature = 23.5 °C

Solid AgCl will be formed

Step 2: The balanced equation:

AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)

AgCl(s) + NaNO3(aq) → Na+(aq) + NO3-(aq) + AgCl(s)

Step 3: Define the formula

Pressure is constant. → the heat evolved from the reaction is equivalent to the enthalpy of reaction.

Q=m*c*ΔT

⇒ Q = the heat transfer (in joule)

⇒ m =the mass (in grams)

⇒ c= the heat capacity (J/g°C)

⇒ ΔT = Change in temperature = T2- T1

Step 4: Calculate heat

Let's vonsider the density the same as the density of water (1g/mL)

Mass = volume * density

Mass = 200 mL * 1g/mL

Mass = 200 grams

Q= m*c*ΔT

⇒ m = 200 grams

⇒ c = the heat capacity (let's consider the heat capacity of water) = 4.184 J/g°C

⇒ ΔT = 23.5 -21.9 = 1.6°C

Q = 200 * 4.184 * 1.6 = 1338 .9 J = 1.3 kJ

There is 1.3 kJ heat produced(released)

Therefore, we assumed no heat is absorbed by the calorimeter, no heat is exchanged between the calorimeter and its surroundings, and the specific heat and mass of the solution are the same as those for water (1g/mL and 4.184 J/g°C)

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2 years ago