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3 years ago

How many tiny frogs sitting next to each other would measure the same length as a Blue Whale?

Chemistry

2 answers:

Naddik [55]3 years ago

8 0

Answer:

LOOK BELOW

Explanation:

Well a female is 82ft and a male is 79ft so we will just go with both answers. A tiny frog is about a estimate length of 0.27 inches so you would have to divide and or multiply 82 by 0.27 getting your first length then do the same with teh next one and thats you answer! hope i helped bby :3

Svetlanka [38]3 years ago

6 0

Answer:

About 2,500

Explanation:

The blue whale is the largest animal on Earth. The length of a blue whale is about 25 m, although is is said the largest confirmed measure is 29.9m.

The tiny frogs measure about 10mm.

You can estimate the number of tiny frogs that have the same length as a blue whale dividing the approximate average length of a blue whale by the approximate average length of the tiny frogs.

First convert 25m to mm:

25m × 1,000mm/m = 25,000 mm

Now, divide:

25,000mm / 10mm = 2,500

Hence, about 2,500 tiny frogs sitting next to each other would measure the same length as a blue whale.

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3 years ago

Read 2 more answers

Given a sample of poly[ethylene-stat-(vinyl acetate)] A.Calculate the mean repeat unit molar mass for a sample of poly[ethylene-

AlladinOne [14]

Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

b) degree of polymerization of the copolymer is 1300

Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively

moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate

moles of vinyl acetate = 12.9 g / 86.09 g/mol

moles of vinyl acetate = 0.1498 mol

moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene

moles of Ethylene = 87.1 g / 28.05 d/mol

moles of Ethylene = 3.1052 mol

Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

Next we calculate the mole percent;

mole percent of vinyl acetate $X_{V}$ = moles of vinyl acetate / total moles

$X_{V}$ = (0.1498 mol / 3.255 mol) × 100

$X_{V}$ = 4.6%

mole percent of Ethylene $X_{E}$ = moles of Ethylene / total moles

$X_{E}$ = (3.1052 mol / 3.255 mol) × 100

$X_{E}$ = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑ $X_{i}$ $M_{i}$

where $X_{i}$ is the fraction ratio and $M_{i}$ is the molecular weight

so or the PEVA

mean repeat unit molar mass M = ( $X_{V}$ $M_{V}$ ) + ( $X_{E}$ $M_{E}$ )

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

M = 30.72 g/mol

Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

Degree of polymerization

$DP_{n}$ = $\frac{M_{n} }{M}$

where $M_{n}$ is the number average molecular weight ( 39,870 g/mol )

so we substitute

$DP_{n}$ = 39,870 g/mol / 30.72 g/mol

$DP_{n}$ = 1297.85 ≈ 1300 { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

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2 years ago

A reaction between liquid reactants takes place at −10.0°C in a sealed, evacuated vessel with a measured volume of 45.0L. Measur

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Explanation:-

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$P=\frac{nRT}{V}=\frac{0.130\times 0.0821\times 263}{45.0}=0.0624atm$

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3 years ago

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Answer:

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Explanation:

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2 years ago

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