The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.
<h3>What is the half-life of a radioactive material?</h3>
The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.
The half-life,
, the age, t, and amount remaining,
, of a radioactive material are related by the formula below:
Half-life of carbon-14 = 6000 years
For the Egyptian papyrus with 63% of its original carbon-14 atoms:
For the Aboriginal charcoal with 22% of its original carbon-14 atoms:

For the Mayan headdress with 79% of its original carbon-14 atoms:

Neanderthal skull with 3% of its original carbon-14 atoms:

Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.
Learn more about half-life at: brainly.com/question/26689704
#SPJ1