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4 years ago

The complexity and variety of organic molecules is due to

Physics

1 answer:

Anastaziya [24]4 years ago

3 0

Answer:

Due to the chemical versatility of carbon atoms

Explanation:

Carbon is a very important element and it is commonly found in many varieties of chemical compounds. They are also found to be present in space in various amount. It is often considered to be versatile because they are capable of forming single, double, as well as triple bonds. This enables them to make single and branched chains. They also form ring chains when combined with other atoms of carbon.

It is because of this versatility of carbon atoms, there forms complex variety of organic molecules.

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Three children are riding on the edge of a merry-go-round that is 182 kg, has a 1.60 m radius, and is spinning at 15.3 rpm. The

Korolek [52]

Answer:

The new angular velocity of the merry-go-round is 18.388 revolutions per minute.

Explanation:

The merry-go-round can be represented by a solid disk, whereas the three children can be considered as particles. Since there is no external force acting on the system, we can apply the principle of angular momentum conservation:

$\left(\frac{1}{2}\cdot M + m_{1}+m_{2} + m_{3} \right)\cdot R^{2}\cdot \dot n_{o} = \left(\frac{1}{2}\cdot M + m_{1} + m_{3})\cdot R^{2}\cdot \dot n_{f}$ (1)

Where:

$M$ - Mass of the merry-go-round, in kilograms.

$m_{1}$ , $m_{2}$ , $m_{3}$ - Masses of the three children, in kilograms.

$R$ - Radius of the merry-go-round/Distance of the children with respect to the center of the merry-go-round, in meters.

$\dot n_{o}$ , $\dot n_{f}$ - Initial and final angular speed, in revolutions per minute.

If we know that $M = 182\,kg$ , $m_{1} = 17.4\,kg$ , $m_{2} = 28.5\,kg$ , $m_{3} = 32.8\,kg$ , $R = 1.60\,m$ and $\dot n_{o} = 15.3\,\frac{rev}{min}$ , then the final angular speed of the system is:

$\dot n_{f} = \dot n_{o}\cdot \left(\frac{\frac{1}{2}\cdot M + m_{1} + m_{2} + m_{3} }{\frac{1}{2}\cdot M + m_{1} + m_{3} } \right)$

$\dot n_{f} = \left(15.3\,\frac{rev}{min} \right)\cdot \left[\frac{\frac{1}{2}\cdot (182\,kg) + 17.4\,kg +28.5\,kg + 32.8\,kg }{\frac{1}{2}\cdot (182\,kg) + 17.4\,kg + 32.8\,kg } \right]$