T = 0.017 s
From the foot to the brain is almost the same as the height. We are not given the height of the woman, but to find "about" how much time, we need a height to work with.
She *could* be 1.7 m <- height = distance
Formula for speed, where k = speed, d = distance, t = time
k = d/t
Rearrange to solve for time:
t = d/k
Substitute known values:
t = (1.7 m) / (100 m/s)
Solve:
t = 0.017 s
Therefore, it takes about 0.017s for the impulse to travel from the foot to the brain.
D-Volatge / gravity and current aren’t units and amperes is the loop of electrical current
Answer:
Part A: ![t = v_0/a_0](https://tex.z-dn.net/?f=t%20%3D%20v_0%2Fa_0)
Part B: ![t = v_0/a_0](https://tex.z-dn.net/?f=t%20%3D%20v_0%2Fa_0)
Part C: ![v_0^2/a_0](https://tex.z-dn.net/?f=v_0%5E2%2Fa_0)
Explanation:
Part A:
We will use the following kinematics equation:
![v = v_0 + at\\0 = v_0 - a_0t\\t = \frac{v_0}{a_0}](https://tex.z-dn.net/?f=v%20%3D%20v_0%20%2B%20at%5C%5C0%20%3D%20v_0%20-%20a_0t%5C%5Ct%20%3D%20%5Cfrac%7Bv_0%7D%7Ba_0%7D)
Part B:
We will use the same kinematics equation:
![v = v_0 + at\\v_0 = 0 + a_0t\\t = \frac{v_0}{a_0}](https://tex.z-dn.net/?f=v%20%3D%20v_0%20%2B%20at%5C%5Cv_0%20%3D%200%20%2B%20a_0t%5C%5Ct%20%3D%20%5Cfrac%7Bv_0%7D%7Ba_0%7D)
Part C:
The total time takes is 2t.
So the train moves a distance of
![x = v_0(2t) = 2v_0(\frac{v_0}{a_0}) = \frac{2v_0^2}{a_0}](https://tex.z-dn.net/?f=x%20%3D%20v_0%282t%29%20%3D%202v_0%28%5Cfrac%7Bv_0%7D%7Ba_0%7D%29%20%3D%20%5Cfrac%7B2v_0%5E2%7D%7Ba_0%7D)
And the car moves a distance in Part A and in Part B:
![d_A = v_0t + \frac{1}{2}at^2 = v_0(\frac{v_0}{a_0}) - \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{a_0} - \frac{v_0^2}{2a_0} = \frac{v_0^2}{2a_0}\\d_B = v_0t + \frac{1}{2}at^2 = 0 + \frac{1}{2}a_0(\frac{v_0^2}{a_0^2}) = \frac{v_0^2}{2a_0}](https://tex.z-dn.net/?f=d_A%20%3D%20v_0t%20%2B%20%5Cfrac%7B1%7D%7B2%7Dat%5E2%20%3D%20v_0%28%5Cfrac%7Bv_0%7D%7Ba_0%7D%29%20-%20%5Cfrac%7B1%7D%7B2%7Da_0%28%5Cfrac%7Bv_0%5E2%7D%7Ba_0%5E2%7D%29%20%3D%20%5Cfrac%7Bv_0%5E2%7D%7Ba_0%7D%20-%20%5Cfrac%7Bv_0%5E2%7D%7B2a_0%7D%20%3D%20%5Cfrac%7Bv_0%5E2%7D%7B2a_0%7D%5C%5Cd_B%20%3D%20v_0t%20%2B%20%5Cfrac%7B1%7D%7B2%7Dat%5E2%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7Da_0%28%5Cfrac%7Bv_0%5E2%7D%7Ba_0%5E2%7D%29%20%3D%20%5Cfrac%7Bv_0%5E2%7D%7B2a_0%7D)
So the total distance that the car traveled is ![d = \frac{v_0^2}{a_0}](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7Bv_0%5E2%7D%7Ba_0%7D)
The difference between the train and the car is
![x - d = \frac{2v_0^2}{a_0} - \frac{v_0^2}{a_0} = \frac{v_0^2}{a_0}](https://tex.z-dn.net/?f=x%20-%20d%20%3D%20%5Cfrac%7B2v_0%5E2%7D%7Ba_0%7D%20-%20%5Cfrac%7Bv_0%5E2%7D%7Ba_0%7D%20%3D%20%5Cfrac%7Bv_0%5E2%7D%7Ba_0%7D)
Answer:
<em>Refraction is the change in direction of waves that occurs when waves travel from one medium to another. ... Diffraction is the bending of waves around obstacles and openings. The amount of diffraction increases with increasing wavelength.</em>