A) mean = np
0.6(200) = 120
SD^2= np(1-p)
SD = sqrt(200(0.6)(1-0.6))
SD = 6.928
B) the mean of binomial distribution in this case is the average number of samples you’ll have to take before you achieve a sample of 200 where 60% of smokers who started smoking before 18.
That would be rolling a 1 and a 2 .
so possibilities are 1 on first die and 2 on the second die
OR 2 on first die and 1 on the second.
Both of these have a probability of 1/6 * 1/6 = 1/36
so required probability = 1/36 + 1/36 = 2/36 = 1/18
1. 5 in and 1/3 in: Area = 5/3 in^2
2. 5 in and 4/3 in: Area= 20/3 in^2
3. 5/2 in and 4/3 in: Area=10/3 in^2
4. 7/6 in and 6/7 in: Area = 1 in^2
Step-by-step explanation:
<u>1. 5 in and 1/3 in</u>
Here,
<u>2. 5 in and 4/3 in</u>
Here,
<u>3. 5/2 in and 4/3 in</u>
<u>4. 7/6 in and 6/7 in</u>
<u>Let</u>
<u>Hence,</u>
1. 5 in and 1/3 in: Area = 5/3 in^2
2. 5 in and 4/3 in: Area= 20/3 in^2
3. 5/2 in and 4/3 in: Area=10/3 in^2
4. 7/6 in and 6/7 in: Area = 1 in^2
Keywords: Rectangle, Area
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Answer:
tenths.........
Step-by-step explanation:
.....is the answer
Answer:
-790
Step-by-step explanation: