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4 years ago

Mercury-203 undergoes beta minus decay. The subscript in the nuclide notation, Hg, is _____.

Chemistry

2 answers:

lilavasa [31]4 years ago

6 0

Answer:

80 Tl 203 81

Explanation:

correct on edge 2020 (fyi its a lowercase L for answer number 2)

Ganezh [65]4 years ago

5 0

1. The subscript when writing the notation is always dedicated to the atomic number of the element. Since the atomic number for Mercury, Hg, is 80, then the subscript is 80.

2. For the second problem, you just have to balance out the subscripts and superscripts of the reactions.

Superscripts: 203 = 203 + ?; To balance, the missing number would be 0.
Subscripts: 80 = 81 + ?; To balance, the missing number would be -1.
Hence the particle produced is actually an electron, or a beta particle (not an element). The mass number is 0, and the atomic number is 0 (since it does not contain any proton).

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tekilochka [14]

Answer:

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3 years ago

The pH of a 0.78M solution of 4-pyridinecarboxylic acid HC6H4NO2is measured to be 2.53.Calculate the acid dissociation constant

nika2105 [10]

Answer : The value of acid dissociation constant is, $1.1\times 10^{-5}$

Solution : Given,

Concentration pyridinecarboxylic acid = 0.78 M

pH = 2.53

First we have to calculate the hydrogen ion concentration.

$pH=-\log [H^+]$

$2.53=-\log [H^+]$

$[H^+]=2.95\times 106{-3}M$

Now we have to calculate the acid dissociation constant.

The equilibrium reaction for dissociation of (weak acid) is,

$HC_6H_4NO_2\rightleftharpoons C_6H_4NO_2^-+H^+$

initially conc. 0.78 0 0

At eqm. (0.78-x) x x

The expression of acid dissociation constant for acid is:

$k_a=\frac{[C_6H_4NO_2^-][H^+]}{[C_6H_4NO_2]}$

As, $[H^+]=[C_6H_4NO_2^-]=x$

So, $x=2.95\times 106{-3}M$

Now put all the given values in this formula ,we get:

$k_a=\frac{(x)\times (x)}{(0.78-x)}$

$k_a=\frac{(2.95\times 106{-3})\times (2.95\times 106{-3})}{(0.78-2.95\times 106{-3})}$

$K_a=1.1\times 10^{-5}$

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4 years ago

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Answer:

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Florine and chorine=gas

Bromine=liquid

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HOPE IT is right

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Karo-lina-s [1.5K]

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