Answer:

Explanation:
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In this case, since the reaction for the formation of ammonia is:

We can evidence the 1:2 mole ratio of nitrogen gas to ammonia; therefore, the appropriate stoichiometric setup for the calculation of the moles of the latter turns out to be:

And the result is:

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Explanation:
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Answer:
The resulting solution is basic.
Explanation:
The reaction that takes place is:
First we <u>calculate the added moles of HNO₃ and KOH</u>:
- HNO₃ ⇒ 12.5 mL * 0.280 M = 3.5 mmol HNO₃
- KOH ⇒ 5.0 mL * 0.920 M = 4.6 mmol KOH
As <em>there are more KOH moles than HNO₃,</em> the resulting solution is basic.