The vertex form is
f(x) = a(x - (-1))^2 - 108 = a(x + 1)^2 - 108 where a is some constant.
from the y intercept x = 0 when f(x) = -105, so substituting:-
-105 = a (0+1)^2 - 108
a = -105+108 = 3
so our equation is f(x) = 3(x + 1)^2 - 108
for x intercept:-
3(x +1)^2 - 108 = 0
(x + 1)^2 = 108 / 3 = 36
x+ 1 = +/- sqrt36 = +/- 6
x = -7 or 5
so the x intercepts are at ( (-7,0) and (5,0)
Answer:
![24\sqrt{5}\ yards](https://tex.z-dn.net/?f=24%5Csqrt%7B5%7D%5C%20yards)
Step-by-step explanation:
Let A1 be the area of one square and A2 be the area of second square
So,
A1 = s^2
where s is side of square
![s^2=125\\\sqrt{s^2}=\sqrt{125}\\s=\sqrt{25*5}\\ s= \sqrt{5^2 * 5}\\ s= 5\sqrt{5}](https://tex.z-dn.net/?f=s%5E2%3D125%5C%5C%5Csqrt%7Bs%5E2%7D%3D%5Csqrt%7B125%7D%5C%5Cs%3D%5Csqrt%7B25%2A5%7D%5C%5C%20s%3D%20%5Csqrt%7B5%5E2%20%2A%205%7D%5C%5C%20s%3D%205%5Csqrt%7B5%7D)
So side of one square is ![5\sqrt{5}](https://tex.z-dn.net/?f=5%5Csqrt%7B5%7D)
To calculate the length of fence we need to find the perimeter of the square
So,
P1 = 4 * s
![=4*5\sqrt{5} \\=20\sqrt{5}](https://tex.z-dn.net/?f=%3D4%2A5%5Csqrt%7B5%7D%20%5C%5C%3D20%5Csqrt%7B5%7D)
For second square:
![A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}](https://tex.z-dn.net/?f=A_2%3Ds%5E2%5C%5C5%3Ds%5E2%5C%5C%5Csqrt%7Bs%5E2%7D%3D5%5C%5C%7Bs%7D%3D%5Csqrt%7B5%7D)
The perimeter will be:
![P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}](https://tex.z-dn.net/?f=P_2%20%3D%204%2As%5C%5C%3D4%20%2A%20%5Csqrt%7B5%7D%20%5C%5C%3D4%5Csqrt%7B5%7D)
So the total fence will be: P1+P2
![= 20\sqrt{5}+4\sqrt{5} \\= 24\sqrt{5}\ yards](https://tex.z-dn.net/?f=%3D%2020%5Csqrt%7B5%7D%2B4%5Csqrt%7B5%7D%20%5C%5C%3D%2024%5Csqrt%7B5%7D%5C%20yards)
let the third factor be a
(x+1)(x-2)(a)=2x^3-x^2-5x-2
(x^2-x-2)(a)=2x^3-x^2-5x-2
a=(2x^3-x^2-5x-2)/(x^2-x-2)
a=2x+1
third zero = -1/2
HOPE THIS WILL HELP U
The sides of central angles will=always be congruent.
The sides of inscribed angles will=sometimes be congruent.
Answer:
8 bags
7 green marbles and 3 yellow marbles
Step-by-step explanation:
Find the GCF of 24 and 56
24 = 4 x 6
= 2 x 2 x 2 x 3
56 = 7 x 8
= 7 x 4 x 2
= 7 x 2 x 2 x 2
The common factors are - 2 x 2 x 2, which is 8.
So the greatest number of bags they can make is 8
Divide the amount of marbles by the number of bags
24 yellow marbles and 8 bags, so 24/8 is 3
56 green marbles and 8 bags, so 56/8 is 7
Hope this helps, let me know if you have any questions