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d1i1m1o1n [39]
4 years ago
15

At what condition the screw gauge dors not have zero error

Physics
1 answer:
lana66690 [7]4 years ago
6 0
<span>The screw gauge doesn’t have a zero error when the zero of the main scale coincides with the zero of the vernier scale or circular scale.
 In case they don’t coincide then the instrument screw gauge is said to have a zero error which can be positive zero error or a negative zero error. In order to get an exact measurement, the error is added or subtracted from the value measured.</span>
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Pls help 100 points plssssssss
natima [27]

Answer:

d

Explanation:

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Which of the following explanations accounts for why the Plateau of Tibet is a desert?
Svetllana [295]

Answer:

a

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4 years ago
The dragster has a mass of 1.3 Mg and a center of mass at G. A parachute is attached at C provides a horizontal braking force of
adell [148]

Answer:

The deceleration of the dragster upon releasing the parachute such that the wheels at B are on the verge of leaving the ground is  16.33 m/s²

Explanation:

The additional information to the question is embedded in the diagram attached below:

The height between the dragster and ground is considered to be 0.35 m since is not given ; thus in addition win 0.75 m between the dragster and the parachute; we have: (0.75 + 0.35) m = 1.1 m

Balancing the equilibrium about point A;

F(1.1) - mg (1.25) = ma_a (0.35)

1.8v^2(1.1) - 1200(9.8)(1.25) = 1200a(0.35)

1.8v^2(1.1) - 14700 = 420 a   ------- equation (1)

F_x = ma_x \\ \\ = 1.8v^2 = 1200 \ a             --------- equation (2)

Replacing equation 2 into equation 1 ; we have :

{1.1 * 1200 \ a} - 14700 = 420 a

1320 a - 14700 = 420 a

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The deceleration of the dragster upon releasing the parachute such that the wheels at B are on the verge of leaving the ground is  16.33 m/s²

5 0
3 years ago
Question 11 Saved
BaLLatris [955]
2is the right anwser


8 0
3 years ago
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2. An airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind
Alex777 [14]

The resultant speed of the plane  is (3) 226 m/s

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We can calculate the resultant speed of the plane by using the Pythagorean Theorem since both speeds are perpendicular (forming a right triangle).

So, calculating we have:

ResultantSpeed=\sqrt{VerticalSpeed^{2}+HorizontalSpeed^{2}}\\\\ResultantSpeed=\sqrt{(220\frac{m}{s})^{2}+50\frac{m}{s})^{2}

ResulntantSpeed=\sqrt{48400\frac{m^{2} }{s^{2} }+2500\frac{m^{2} }{s^{2} } } \\\\ResultantSpeed=\sqrt{50900\frac{m^{2} }{s^{2} }}=226\frac{m}{s}

Hence, we have that the resultant speed of the plane  is (3) 226 m/s

Have a nice day!

5 0
3 years ago
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