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sveticcg [70]
3 years ago
8

Explain how star clusters help us understand the stages of stellar evolution

Physics
1 answer:
expeople1 [14]3 years ago
5 0

Answer: More specifically, the term is typically defined as a period when gross domestic product (GDP) declines for two consecutive quarters. This prevailing line of thought was popularized by economist Julius Shiskin in 1974.

Explanation:

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What would happen if you tried to use a prism to disperse a beam that contained only green light?​
Margaret [11]

It is determined by the nature of the green light. Because lasers create light at almost a single frequency, green laser light would appear as a thin line of pure green. Other sources of "green" light emit light at a variety of frequencies, including yellow and blue, resulting in a strong green band in the center that fades into blue-green and yellow-green at the borders.

For example, here’s a graph of the spectrum of a green LED, showing the color range: Attachment #1

and here’s a graph of the transmission spectra of several standard photographic filters, including green: Attachment #2

Learn more about the color spectrum:

  • brainly.com/question/14552374
  • brainly.com/question/20930002

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4 0
2 years ago
The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental
pav-90 [236]

A) 5.0\cdot 10^{-11} m

The energy of an x-ray photon used for single dental x-rays is

E=25 keV = 25,000 eV \cdot (1.6\cdot 10^{-19} J/eV)=4\cdot 10^{-15} J

The energy of a photon is related to its wavelength by the equation

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34}Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

Re-arranging the equation for the wavelength, we find

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15}J}=5.0\cdot 10^{-11} m

B) 2.0\cdot 10^{-11} m

The energy of an x-ray photon used in microtomography is 2.5 times greater than the energy of the photon used in part A), so its energy is

E=2.5 \cdot (4\cdot 10^{-15}J)=1\cdot 10^{-14} J

And so, by using the same formula we used in part A), we can calculate the corresponding wavelength:

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14}J}=2.0\cdot 10^{-11} m

4 0
3 years ago
Why is physics an important part of history
tigry1 [53]

Answer:

History and physics are intertwined through all the revolutionary thinkers, scientists, and people who studied these ideas. For example, many historical thinkers such as Isaac Newton and Galileo Galilei not only had revolutionary ideas, but they also changed life forever as the people knew it. It shocked the people and taught them new things, and upset the church.

Explanation:

8 0
4 years ago
Read 2 more answers
An electron in a cathode-ray beam passes between 2.5cm long parallel-plate electrodes that are 6.0mm apart. A 2.1mT, 2.5-cm-wide
Dmitry_Shevchenko [17]

Answer:

(a). The speed of electron is 1.56\times10^{7}\ m/s.

(b). The radius of electron is 4.2\ cm

Explanation:

Given that,

Length = 2.5 cm

Distance = 6.0 mm

Magnetic field = 2.1 T

Potential difference = 700 V

(a). We need to calculate the electron's speed

Using formula of speed

v=\sqrt{\dfrac{2eV}{m}}

Put the value into the formula

v=\sqrt{\dfrac{2\times1.6\times10^{-19}\times700}{9.1\times10^{-31}}}

v=15689290.81\ m/s

v=1.56\times10^{7}\ m/s

(b). We need to calculate the radius of electron

Using formula of centripetal force

\dfrac{mv^2}{r}=qvB

r=\dfrac{mv}{qB}

Where,

m = mass of electron

v = speed of electron

r = radius

q = charge of electron

B = magnetic field

Put the value into the formula

r=\dfrac{9.1\times10^{-31}\times1.56\times10^{7}}{1.6\times10^{-19}\times2.1\times10^{-3}}

r=0.042\ m

r=4.2\ cm

Hence, (a). The speed of electron is 1.56\times10^{7}\ m/s.

(b). The radius of electron is 4.2 cm

8 0
3 years ago
How many times louder is the intensity of sound at a rock concert in comparison with that of a whisper, if the two intensity lev
Phoenix [80]

Answer:

 5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper

Explanation:

Given that at a rock concert;

the intensity of sound is 110 dB compared to a whisper of 3 dB

Now; how many times louder will that of the whisper be compared to the sound of the rock concert

Using the formula for calculating decibels (dB);

For 110 dB

dB = 10log₁₀(W)

110 dB =  10^{(110/10)}

110 dB = 10¹¹

For 3dB

dB = 10log₁₀(W)

3 dB = 10^{(3/10)}

3 dB = 2

Now:

(110/3)dB = 10¹¹/2

(110/3)dB =  5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper

7 0
3 years ago
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