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Katen [24]
3 years ago
10

Two very flat, metallic plates separated a distance d have a potential difference of 600 Volts between them as shown below. A pr

oton and positron (which is a positively charged electron) are released from rest at the surface of the metal plate held at 600 Volts. Which of the following statement(s) is (are) correct?
I. The positron's acceleration is larger than the proton's acceleration.
II. The positron's acceleration is the same as the proton's acceleration.
III. The positron's acceleration is smaller than the proton's acceleration.
IV. The positron's kinetic energy will be larger than the proton's kinetic energy right before the particles hit the 0 Volt plate.
V. The positron's kinetic energy will be the same as the proton's kinetic energy right before the particles hit the 0 Volt plate.
VI. The positron's kinetic energy will be smaller than the proton's kinetic energy right before the particles hit the 0 Volt plate.
Physics
1 answer:
Jobisdone [24]3 years ago
4 0

<h2>The acceleration of positron will be larger than that of proton</h2>

Explanation:

When proton or positron are released in between two parallel plates .

The force of proton = q E

here q is the charge and E is the electric field intensity between the plates

Thus m a = q E   or  a = q E/m ; here m is the mass of proton

Similarly the acceleration of positron = q E/m₀

here m₀ is the mass of positron

The mass of positron is much smaller than proton .

Thus acceleration of positron is much larger than that of proton.

The energy of proton = q V

here q is the charge on proton and V is the potential difference applied

Similarly , the energy of positron = q V

Here charge and potential on the positron is the same as that of proton .

Thus there energy will be same .

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A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac
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Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

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A 1.11 kg piece of aluminum at 78.3 c is put into a glass with 0.210 kg of water at 15.0
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M = mass of aluminium = 1.11 kg

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T_{wi} = initial temperature of water = 15 c

T = final equilibrium temperature = ?

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What is the acceleration of a 0.30-kg volleyball when a player uses a force of 42 N to spike the ball?
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So, substituting these values into the equation,

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