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algol13
4 years ago
6

The sun’s___and the planet’s___keeps planets moving is___orbits.

Physics
1 answer:
Sauron [17]4 years ago
8 0

The sun’s gravitational attraction and the planet’s inertia keeps planets moving is circular orbits.

Explanation:

The planets in the Solar System move around the Sun in a circular orbit. This motion can be explained as a combination of two effects:

1) The gravitational attraction of the Sun. The Sun exerts a force of gravitational attraction on every planet. This force is directed towards the Sun, and its magnitude is

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M is the mass of the Sun

m is the mass of the planet

r is the distance between the Sun and the planet

This force acts as centripetal force, continuously "pulling" the planet towards the centre of its circular orbit.

2) The inertia of the planet. In fact, according to Newton's first law, an object in motion at constant velocity will continue moving at its velocity, unless acted upon an external unbalanced force. Therefore, the planet tends to continue its motion in a straight line (tangential to the circular orbit), however it turns in a circle due to the presence of the gravitational attraction of the Sun.

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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Charge q1 is distance s from the negative plate of a parallel-plate capacitor. Charge q2=q1/3 is distance 2s from the negative p
Svetlanka [38]

Answer:

The ratio (U₁/U₂) = 6

Explanation:

U, the potential energy is given as

U = kqQ/r

k = Coulomb's constant

q = charge we're concerned about

Q = charge of the negative plate of the capacitor

r = distance of q from the negative plate of the capacitor.

For charge q₁

U₁ = kq₁Q/s

U₂ = kq₂Q/2s

But q₂ = q₁/3

U₂ becomes U₂ = kq₁Q/6s

U₁ = kq₁Q/s

U₂ = kq₁Q/6s

(U₁/U₂) = 6

5 0
4 years ago
Compare the weight of a 5.00-kg object on Earth’s surface to the gravitational force between a 5.00-kg object that is one Earth
makkiz [27]

Answer

given,

mass of an object = 5 Kg

mass of the other object = 5.98 x 10²⁴ Kg

radius of earth = 6371 Km = 6.371 x 10⁶ m

comparison between gravitational force between two object and weight of the object.

gravitational force between two objects

   F = \dfrac{Gm_1m_2}{r^2}

   F = \dfrac{6.67 \times 10^{-11}\times 5 \times 5.98 \times 10^{24}}{(6.371 \times 10^6)^2}

      F = 49.134 N

weight of the object on the earth surface

  F = m g

  F = 5 x 9.81

  F = 49.05 N

From the above two calculation we can conclude that gravitational force is approximately equal to weight of the body.

5 0
3 years ago
The electric potential inside a charged spherical conductor of radius R is is given by V = keQ/R, and the potential outside is g
Bumek [7]

Answer:

For outer points of shell

E = \frac{k_eQ}{r^2}

Now for inner point of shell

E = 0

Explanation:

As we know that out side the shell electric potential is given as

V = \frac{K_e Q}{r}

inside the shell the electric potential is given as

V = \frac{K_e Q}{R}

now we know the relation between electric potential and electric field as

E = - \frac{dV}{dr}

so we can say for outer points of the shell

E = -\frac{dV}{dr}

E = - \frac{d}{dr}(\frac{K_eQ}{r})

E = \frac{k_eQ}{r^2}

Now for inner point again we can use the same

E = - \frac{dV}{dr}

E = - \frac{d}{dr}(\frac{K_eQ}{R})

E = 0

6 0
3 years ago
Which law describes the interactions between charged particles when they are not in contact?
natulia [17]
The answer would be the coulombs law.

7 0
3 years ago
Read 2 more answers
A spring extends by 10cm when a mass of 100g is attached to it. What is the spring constant?​
pishuonlain [190]

Answer:

10N/m

Explanation:

Using F=kx

F=mg

k=mg/x

k=0.1*10/0.1 (kg*m/s^2)/m

10N/m

8 0
3 years ago
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