Answer:
1p 2p 2p 2p 5p 5p 10p
Step-by-step explanation:
Available coins that are less than 11p: 1p 2p 5p 10p
11p with two coins ⇒ 1p + 10p only
11p with three coins ⇒ 1p + 5p + 5p only
11p with three coins ⇒ 2p + 2p + 2p + 5p only
Therefore, the seven coins that Luke has are:
1p 2p 2p 2p 5p 5p 10p
<span>p + h = 49
h = p + 11
p + p + 11 = 49
2p = 38
Preston has 19 games
Horatio has 30</span>
Check the picture.
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"
2.3s + 4.6h = 4232
s + h = 1030
h = 1030 - s
2.3s + 4.6(1030 - s) = 4232
2.3s + 4738 - 4.6s = 4232
4738 - 4232 = 4.6s - 2.3s
506 = 2.3s
s = 220
h = 1030 - s
h = 1030 - 220 = 810
there were 810 downloads of the high-quality version
Answer:
The correct options are 1, 2 and 4.
Step-by-step explanation:
The given triangle is an equilateral triangle. All the sides of an equilateral triangle are same. All interior angles are equal with measure 60 degree.
The distance from the center of an equilateral triangle to the midpoint of a side is known as apothem. In the given figure letter a represents the apothem.
Point D is the midpoint of BC,

Use Pythagorean theorem in triangle COD. So, option 1 is correct.





The distance can not be negative, so the length of the apothem is approximately 2.5 cm. Option 4 is correct.
The line OC bisects the angle C.



Therefore option 2 is correct.
The perimeter of an equality triangle is

Option 3 is incorrect.

Option 5 is incorrect.
Therefore options 1, 2 and 4 are correct.