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jonny [76]
3 years ago
7

25 POINTS:)

Chemistry
1 answer:
Digiron [165]3 years ago
6 0
I suppose that the answer is A
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The reaction between nitric oxide and oxygen is described by the following chemical equation: Suppose a two-step mechanism is pr
muminat

Answer:

2NO(g) + O2(g) ---> 2NO2(g)

Explanation:

The mechanism for this reaction involves two elementary reactions in which both are bimolecular as shown below;

NO(g) +O2(g) ----> NO2(g) + O(g)

NO(g) + O(g) ----> NO2(g)

Hence overall balanced reaction equation;

2NO(g) + O2(g) ---> 2NO2(g)

7 0
3 years ago
The mass % of Ca in CaSO4 is 29.45%. To calculate the mass of Ca present in a 25.6-g sample of this compound, the correct proced
Rufina [12.5K]

Answer:

The correct answer is - 29.45 / 100 x 25.6 = 7.5392 grams

Explanation:

It is given in the question that in 100 gms of CaSO4 there are 29.45 grams of Ca present and there is 25.6 gram of total CaSO4 sample present, So, to calculate the exact value of calcium in this given sample is:

mass of Ca = total amount of sample*percentage of calcium in sample /100

M of Ca =25.6*29.45/100

M of Ca = 7.5392 grams

Thus, the correct procedure is given by 29.45 / 100 x 25.6 = 7.5392 grams

6 0
3 years ago
The elements lithium and oxygen react explosively to form lithium oxide,Li2O. how many moles of lithium oxide will form if 4.37
anygoal [31]

From the equation,

4 mole of lithium produces 2 mole of lithium oxide

4.37 mol of lithium produces (4.37÷4)x2 mol of lithium oxide

5 0
3 years ago
How many moles of hci are needed to form 230 moles of ci2?
LekaFEV [45]
<span>The answer is 335 dm³.</span>
4 0
3 years ago
How much heat energy is needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C? The specific heat of cadmium is
Ilia_Sergeevich [38]
Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the change in temperature. It is expressed as: 

<span>Energy = mCΔT
</span><span>Energy = 59.7 (0.231) (100-25)
</span><span>Energy = 1034.30 J</span>
3 0
3 years ago
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