Water, H₂O, will have the highest melting point.
Explanation:
So here we have listed the hydrides of oxygen, sulphur, selenium and tellurium.
From this elements oxygen have the highest electronegativity and as a consequence the oxigen hydride (water, hydrogen dioxide) it is able to form hydrogen bonds between molecules. So you need more energy to overcome the interactions between molecules in water that for the other compounds.
Water, H₂O, will have the highest melting point between the listed hydrides.
Learn more about:
hydrogen bonds
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<span>Electronegativity values are useful in determining if a bond is to be classified as nonpolar covalent, polar covalent or ionic. The electronegativities of oxygen and nitrogen are respectively, 3.44 and 3.04 on Pauling scale, the electronegativity difference being, 0.4. The bond is considered to be non-polar covalent.
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Extensive properties, such as mass and volume, depend on the amount of matter being measured.Intensive properties, such as density and color, do not depend on the amount of the substance present.Physical properties<span> can be measured without changing a substance's chemical identity.</span>
Answer is: an oxybromate compound is KBrO₄ (x = 4).
ω(Br) = 43.66% ÷ 100%.
ω(Br) = 0.4366; mass percentage of bromine.
If we take 100 grams of compound:
m(Br) = ω(Br) · 100 g.
m(Br) = 0.4366 · 100 g.
m(Br) = 43.66 g; mass of bromine.
n(Br) = m(Br) ÷ M(Br).
n(Br) = 43.66 g ÷ 79.9 g/mol,
n(Br) = 0.55 mol; amoun of bromine.
From chemical formula (KBrOₓ), amount of potassium is equal to amount of bromine: n(Br) = n(K).
m(K) = 0.55 mol · 39.1 g/mol.
m(K) = 21.365 g; mass of potassium in the compound.
m(O) = 100 g - 21.365 g - 43.66 g.
m(O) =34.97 g; mass of oxygen.
n(O) = 34.97 g ÷ 16 g/mol.
n(O) = 2.185 mol.
n(K) : n(Br) : n(O) = 0.55 mol : 0.55 mol : 2.185 mol /÷ 0.55 mol.
n(K) : n(Br) : n(O) = 1 : 1 : 4.