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soldier1979 [14.2K]
2 years ago
13

Show how to carry out the transformation in the highest yield possible. Select the appropriate reagents and draw the correct org

anic product at each step.
Chemistry
1 answer:
kherson [118]2 years ago
8 0

We want to use this primary leaving group on this primary starting material because it will give us a greater yield and say, if we were to use a secondary reagent in place of this primary.

Now we've moved on from our fundamentals. So we have our starting material and we have That's our beautiful sec futile ether. So now that we've written out are starting material, we can take a thing about where exactly some reactivity may happen. So, for example, could start out with an alcohol that looks as the following. This is a secondary alcohol you can see. So now we need to take a look at some of alcohol.

So now we need to think about our alcohol. Hey, light again. Well, we'll have a hey light. That's a very good leaving group. So we need alcohol. So for example, so now we have a primary structure here, So this will undergo and s and two reaction due to the lacking of hysteric hindrance. Formal negative charge attacks that electrical it carbon bro.

Learn more about Alcohol here-

brainly.com/question/14229343

#SPJ4

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8 0
2 years ago
Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
faltersainse [42]

Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

3 0
3 years ago
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