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soldier1979 [14.2K]
2 years ago
13

Show how to carry out the transformation in the highest yield possible. Select the appropriate reagents and draw the correct org

anic product at each step.
Chemistry
1 answer:
kherson [118]2 years ago
8 0

We want to use this primary leaving group on this primary starting material because it will give us a greater yield and say, if we were to use a secondary reagent in place of this primary.

Now we've moved on from our fundamentals. So we have our starting material and we have That's our beautiful sec futile ether. So now that we've written out are starting material, we can take a thing about where exactly some reactivity may happen. So, for example, could start out with an alcohol that looks as the following. This is a secondary alcohol you can see. So now we need to take a look at some of alcohol.

So now we need to think about our alcohol. Hey, light again. Well, we'll have a hey light. That's a very good leaving group. So we need alcohol. So for example, so now we have a primary structure here, So this will undergo and s and two reaction due to the lacking of hysteric hindrance. Formal negative charge attacks that electrical it carbon bro.

Learn more about Alcohol here-

brainly.com/question/14229343

#SPJ4

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How many valence electrons does Carbonic Acid contain?
geniusboy [140]
4 carbon electrons. Hope this helps have a nice day
6 0
3 years ago
A teapot with a surface area of 785 cm2 is to be plated with silver. It is attached to the negative electrode of an electrolytic
lina2011 [118]

Answer:

Given info: The surface area of teapot plated with silver is 700 cm2700 cm2, the cell is powered by 12.0-V12.0-V, the resistance of the cell is 1.80 Ω1.80 Ω, thickness of silver layer is 0.133-mm0.133-mm and density of silver is 10.5×103 kg/m310.5×103 kg/m3.

Write the expression for the mass of the silver.

m=ρAdm=ρAd (1)

Here,

ρρ is the density of silver.

AA is the surface area.

dd is the thickness of the silver layer.

Substitute 10.5×103 kg/m310.5×103 kg/m3 for ρρ, 700 cm2700 cm2 for AA and 0.133-mm0.133-mm for dd in equation (1) to find mass of the silver.

m=(10.5×103 kg/m3)(700 cm2(10−21 cm)2)(0.133-mm(10−3 m1 mm))=0.0978 kg(103 g1 kg)=97.8 gm=(10.5×103 kg/m3)(700 cm2(10−21 cm)2)(0.133-mm(10−3 m1 mm))=0.0978 kg(103 g1 kg)=97.8 g

Thus, the mass of silver is 97.8 g97.8 g.

Write the expression for number of moles of silver.

n=mWan=mWa (2)

Here,

mm is the mass of silver.

WaWa is the atomic weight.

The atomic weight of silver is 107.8 g/mole107.8 g/mole

Substitute 97.8 g97.8 g for mm, and 107.8 g/mole107.8 g/mole for WaWa in equation (2) to find number of moles of silver.

n=97.8 g107.8 g/mole=0.907 moln=97.8 g107.8 g/mole=0.907 mol

Thus, the number of moles of silver is 0.907 mol0.907 mol.

7 0
4 years ago
2 NaOH + H2SO4 → 2 H2O + Na2SO4<br> How many grams of water are produced from 203.50 grams of H2S04?
ddd [48]

Answer:

m_{H_2O}=74.8gH_2O

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible to realize there is a 1:2 mole ratio of sulfuric acid to water; thus, given the mass of the former and its molar mass (98.07 g/mol), it is possible to determine the mass of produced water as shown below:

m_{H_2O}=203.50gH_2SO_4*\frac{1molH_2SO_4}{98.07gH_2SO_4}*\frac{2molH_2O}{1molH_2SO_4}  *\frac{18.02gH_2O}{1molH_2O}\\\\m_{H_2O}=74.8gH_2O

Regards!

6 0
3 years ago
Which compounds give a 1h nmr spectrum with two signals in a ratio of 2:3?
spayn [35]

Four option are provided as,

CH3CH2OCH2CH3

CH3CH2Cl

CH3CH2CH3

CH3OCH2CH2OCH3


CH3CH2Cl having 2 peaks of H NMR as 1st peak for quartet of 2 H and 2nd peak of triplet of 3 H and thus the ratio of both the peak is 2 :3 as the ratio indicates the number of hydrogen corresponds to each peak.


8 0
4 years ago
Which is the correct chemical equation for the following statement? “Sodium reacts with oxygen in a 2 to 1 ratio to produce sodi
den301095 [7]
I think answer youre looking for is 2Na+O->Na2O . But sadly it is wrong since we dont use  atomic oxygen in reactions. It should be rather
4Na+O2 => 2Na2O but it doesnt correspond to ratios given.
4 0
3 years ago
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