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Studentka2010 [4]
3 years ago
7

How much heat is absorbed in the complete reaction of 3.00 grams of SiO2 with excess carbon in the reaction SiO2(g) + 3C(s) → Si

C(s) + 2CO(g) ΔH° = 624.7 kJ/mol?
Chemistry
1 answer:
defon3 years ago
6 0

Answer:

31.24 kJ

Explanation:

  • SiO₂(g) + 3C(s) → SiC(s) + 2CO(g)        ΔH° = 624.7 kJ/mol

First we <u>convert 3.00 grams of SiO₂ to moles</u>, using its <em>molar mass</em>:

  • 3.00 g SiO₂ ÷ 60.08 g/mol = 0.05 mol

Now we <u>calculate the heat absorbed</u>, using the <em>given ΔH°</em>:

If the complete reaction of 1 mol of SiO₂ absorbs 624.7 kJ, then with 0.05 mol:

  • 0.05 mol * 624.7 kJ/mol = 31.24 kJ of heat would be absorbed.
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A substance that is made up of two or more different types of atoms bonded together is a
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Answer: B

Explanation:

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How is a niche different than a habitat?
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Answer:

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Explanation:

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7 0
4 years ago
Calculate the mass percent of a NaCl solution in which 140g of NaCl is dissolved in 4.50L of water at 25C (density = 0.997g/mL).
Lemur [1.5K]
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% mass = 140 g NaCl / (140 g NaCl + 4500 mL ( 0.997 g/mL)) x 100
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6 0
4 years ago
Calculate freeze 62.9 g of iron at 1535oC<br> Hf (J/g)=257
Inessa [10]

Answer:

<u>-16200J</u>

Explanation:

(257J/g)(62.9g)

eliminate the variables

u get 16165.3

go to 3 significant digits

u get 16200

and since it is freezing we are taking out energy so it would be

-16200J

4 0
4 years ago
How many moles of each substance are needed to prepare the following solutions?
Afina-wow [57]
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mass g = 45.0 x 7.5 / 100

mass g = 337.5 / 100 => 3.375 g

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moles KCl ---------------- 3.375 g

moles KCl = 3.375 x 1 / 74.55 => 0.0452 moles of KCl
______________________________________________

b) 9.5 % ( m / V ) :

9.5 g -------- 100 mL ( solution )
mass g ------ 400.0 mL

mass g = 400.0 x 9.5 / 100

mass g = 3800 / 100 => 38 g

1 mole acetic acid -------------- 60.05 g
moles acetid acid  ---------------- 38 g

moles acetid acid = 38 x 1 / 60.05 => 0.6328 moles of  acetid acid<span> 
</span>______________________________________________________

hope this helps!


4 0
3 years ago
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