Remark
This is a very interesting question. Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.
y = x (1)
3x + 4y = 12 (2)
Put x in for y in equation 2
3x + 4x = 12
7x = 12
x = 12/7
x = 1.714
y = 1.714
Problem A
<em><u>x intercept</u></em>
The x intercept occurs when y = 0
3x + 4(0) = 12
3x = 12 Divide by 3
x = 12/3
x = 4
the x intercept = (4,0)
<em><u>y intercept</u></em>
The y intercept occurs when x =0
3(0) + 4y = 12
4y = 12
y = 12/4
y = 3
y intercept = (0,3)
Problem B
x and y both equal 1.714 so they are also the length of the square's side.
Problem C
See solution above. x =y is the key fact.
x = y = 1.714
Answer:
M=5
B= -4
Step-by-step explanation:
y = mx + b
You want to leave a 15% tip on a meal that cost $15.77.
First, convert the 15% to an actual number that can be used in a calculation. For percents,this is always done by simply dividing the percent (in this case 15%) by 100%.So, the conversational term "15%" becomes 15% / 100% = 0.15 in terms of a real mathematical number.
Second, you need to find out what 15% of your $15.77 meal cost is.This is always done by multiplying 0.15 by $15.77, or
0.15 x $15.77=$2.37.
So, the amount of tip you are going to leave is $2.37.
This makes the total cost of your meal (to write on your charge slip or other payment)
$15.77 + $2.37 = $18.14
$18.14 is your answer
Answer:
13,500
Step-by-step explanation:
1925 x 7 = 13,475
13,475
5 and up means round up so we start at the ones place.
13,500
Hopefully this helps you :)
pls mark brainlest ;)
Step-by-step explanation:
Let x be the length and y be the width of the rectangular plot.
The plot is bounded on one side by a river and on the other three sides by a single-strand electric fence. It means,
x+2y = 1500
x = 1500 - 2y ....(1)
We know that the area of a rectangular plot is given by :
A = xy ....(2)
Put the value of x from equation (1) in (2)
.....(3)
For largest area, differentiate above area equation wrt y.
Put the value of y in equation (1).
x = 1500-2(375)
= 750 m
Put the value of y in equation (3).
Hence, the largest area is 281250 m² and its dimensions are 750 m and 375 m.
