What is the value of 4p − 2, when p = 8

teachers for several classes and a district are told to use a new method for teaching reading while all the other classes use tr

OLEGan [10]

The correct answer is:

Experiment

Explanation:

In an experiment, one group is given a treatment while at least one other group is not. After the treatment is finished, the results of the group that receive the treatment are compared with the results of the group (or groups) that do not receive the treatment, to determine if the treatment had any effect on the group.

In this problem, the different groups are the classes. Some classes use the new method, which is the treatment, while other classes do not. At the end of the year, the reading results of each class are compared to see if the treatment (new method) had any effect.

3 0

3 years ago

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What is a similar triangle?

statuscvo [17]

$\large\text{Hey there!}$

$\large\text{\bf{Similar triangles}}}\large\text{ \underline{are basically} \boxed{\text{triangles that have the same SHAPE}}}\\\boxed{\large\text{but they can still be different. They can still be similar if one them is}}\\\boxed{\large\text{rotated or one of them is reflected image of the other triangle}}\checkmark$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\dag\dfrac{\frak{LoveYourselfFirst}}{:)}$

5 0

3 years ago

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

3 years ago

(02.03)Figure ABC is reflected about the x-axis to obtain figure A'B'C':

faust18 [17]

Answer:

B.(–2, –7)

Step-by-step explanation:

5 0

3 years ago

Eric and Linda are paid 52.25 for they're work. Eric worked 3.5 hours, and Linda worked 2 hours. They split the money according

Ne4ueva [31]

Answer:

$33.25

Step-by-step explanation:

Taking Eric's hours as a ratio to the total hours :

3.5 : 3.5 + 2
3.5 : 5.5
3.5 x 2 = : 5.5 x 2
7 : 11

Multiply the ratio into the amount paid :

52.25 x 7/11
4.75 x 7
$33.25

Eric's share of the money is $33.25

4 0

2 years ago

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